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    Is CH3CHCICO2H just 2-iodobut-2-enoic acid?
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    Yesh it is but by convention wouldn't you write it CH3CHCICOOH? <-There's no O2 group?
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    I think so, ignoring geometric isomerism
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    (Original post by corkskrew)
    Yesh it is but by convention wouldn't you write it CH3CHCICOOH? <-There's no O2 group?
    i've just been given a question sheet, lol.
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    (Original post by Widowmaker)
    Is CH3CHCICO2H just 2-iodobut-2-enoic acid?
    methinks tho hath forgetton a 2 and a H > CH3CH2CHICOOH

    is it not 2-iodo-butan-1-oic acid....or is me just spouttin jiberishas usual
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    no it is an alkene so you are "spouttin jiberishas"
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    o shizzlee...i C
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    (Original post by mik1w)
    I think so, ignoring geometric isomerism
    This one can't have geo isomerism, can it? (has 4 different groups)
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    I think so..you can have the iodine and hydrogen opposite, or the iodine and hydrogen on the same side, either way the double bond cannot rotate so the two species will be distinct I think.... Im not sure now yuo said that
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    (Original post by mik1w)
    I think so..you can have the iodine and hydrogen opposite, or the iodine and hydrogen on the same side, either way the double bond cannot rotate so the two species will be distinct I think.... Im not sure now yuo said that
    I thought about that, but it's impossible to identify cis and trans?
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    yeah, cos all four are seperate. I don't know how you'd name them
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    Just one more guys.
    CH3OOCH2CH3
    ???

    I'm a newbie when it comes to organic, lol.
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    With one oxygen in the middle that would be methoxyethane
    CH3OOCHCH3 would be methyl ethanoate
    not sure about double oxygen in the middle?? meth-dioxy-ethane perhaps? or am i babbling?
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    (Original post by Widowmaker)
    Just one more guys.
    CH3OOCH2CH3
    ???

    I'm a newbie when it comes to organic, lol.
    CHOOCH2CH3 would be Ethylethanoate, but the CH3 at the start does not make sense to me
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    I suppose you could have CH2(OH)OCH2CH3, which would be an ether.
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    (Original post by corkskrew)
    With one oxygen in the middle that would be methoxyethane
    CH3OOCHCH3 would be methyl ethanoate
    not sure about double oxygen in the middle?? meth-dioxy-ethane perhaps? or am i babbling?
    Lol, it might work. -O-O- compounds are called "organic peroxides" apparently, but I can't find anything on their nomenclature.
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    couldnt be a peroxide though could it?

    Edit: yes it could I'm just being a wazzok not drawing it out properly
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    NH4+ (aq) + H2O(1) NH3(aq) + H3O+ (aq)
    For the above reaction we have to find out the PH of the solution , we are given the acid dissosiation constant . What assumptions shall we make here?
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    [HA] = [H+] + [A-]

    The assumption u make is that:

    [H+] = [A-]

    and therefore [H+] + [A-] = [H+]^2
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    (Original post by ram)
    [HA] = [H+] + [A-]

    The assumption u make is that:

    [H+] = [A-]

    and therefore [H+] + [A-] = [H+]^2
    That last line is almost right - [H+] * [A-] = [H+]2

    If you remove the water from your equation you have:

    NH4+ <-> NH3 + H+

    For every NH4+ that dissociates you get one NH3 and one H+

    Ka = "products over reactants"

    Ka = [NH3]*[H+] / [NH4+]

    Assumption made here:
    As [NH3] = [H+] it can be said that...

    Ka = [H+]2 / [NH4+]

    You know Ka, you will have been given the concentration of the NH4+, then rest is just maths
 
 
 
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