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    Can someone help me out with this please....

    2/√6

    rationalize the denominator and simplify i do not understand surds

    Thanks
    Regards
    Tom Lowes
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    multply top and bottom by rt(6) to get rid of surds in the bottom.
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    (Original post by thewebmaster)
    Can someone help me out with this please....

    2/√6

    rationalize the denominator and simplify i do not understand surds

    Thanks
    Regards
    Tom Lowes
    2/(sqrt6) = (2Sqrt6)/(Sqrt6 * Sqrt6) {Multiply top and bottom by Sqrt6) = (2Sqrt6)/6 {6^(1/2) * 6^(1/2) = 6^1 = 6 - Law of addition of indices} = (Sqrt6)/3 {2/6 can be simplified by dividing top and bottom by 2, giving 1/3}
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    2/√6 x √6/√6 = 2√6/√6√6 = 2√6/6 = √6/3
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    ok what about

    2/ 1 + √6

    how do u handle these?
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    you do this:
    (2 / 1+√6) x (1-√6 / 1-√6)
    (2 - 2√6) / (1 - 6)
    (2 - 2√6) / -5
    (2√6 - 2) / 5
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    (Original post by Zuber)
    you do this:
    (2 / 1+√6) x (1-√6 / 1-√6)
    (2 - 2√6) / (1 - 6)
    (2 - 2√6) / -5
    (2√6 - 2) / 5
    Not needed but this can be further simplified to:

    2/5(√6 - 2)

    Just remember, with surds play around with the numbers until the denominator contains no surds, this is always done by multiplying the fraction with the surd on denominator or the conjugate.
 
 
 
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