drawing a sketch bar graph for the values of X helps
in first case
P(X«C1) ≈ 0.025
P(X«0)= 0.0038
P(X«1)= 0.0274
u shud b able to see that only part of the bar for x=1 is included
as this is a discrete distribuition, u cant hav part of a value of X
so C1=0
for the second bit
P(X«C2-1) ≈ 0.975
P(X«8) = 0.9532
P(X«9) = 0.9827
i think its helpful if u write it as
P(X»9) = 1-P(X«8)=0.0468
P(X»10) = 1-P(X«9)=0.0173
in this case again, sketch a bar graph n consider the amount of probability after the discrete value and compare it to 0.025, u can see that only part of bar for X=9 is included..
so C2=10
n CR is X«0 or X»10