Question help please and if you would explain please. Thanks
a sample of limestone (impure calcium carbonate) weighing 0.20g was reacted with 50cm3 of 0.10 mol dm-3 Hydrochloric acid
CaCO3 + 2HCL = CaCl2 + CO2 + H2O
The hydrochloric acid was in excess, and this excess just reacted with 14cm3 of 0.10 mol dm-3 sodium hydroxide.
A) what excess volume of 0.10 mol dm-3 hydrochloric acid reacted with 14cm3 of 0.10 mol dm-3 sodium hydroxide?
Bi) what volume of 0.10 mol dm-3 hydrochloric acid reacted with the calcium carbonate in the limestone?
ii) how many moles of hydrochloric acid reacted with the calcium carbonate?
iii)how mant moles of calcium carbonate reacted with hydrochloric acid?
iv) what mass of calcium carbonate reacted?