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P6-red alert-Taylor and Maclaurin series watch

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    i have appeneded my problems in the form of an pdf file.
    all ur help would be appreciated. the ones in blue coloured font are my problem areas. there are total of about 4 questions.
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  1. File Type: pdf taylor and maclaurin series.pdf (42.5 KB, 150 views)
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    Q13(b)e^{-tanx}=e^{tan(-x)} as tanx is an odd function. Thus, simply reverse x with -x in your expansion, so even powers stay the same and odd ones change.

    Q17(c)If (1-x^{2})^{\frac{-1}{2}} = \frac{3}{4}\sqrt{2}
    then \sqrt{2}=\frac{4}{3}(1-x^{2}}^{\frac{-1}{2}}
    You simply need to replace (1-x^{2}}^{\frac{-1}{-2}} with your expansion and set x=\frac{1}{3}
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    (Original post by Gaz031)
    Q17(c)If (1-x^{2})^{\frac{-1}{2}} = \frac{3}{4}\sqrt{2}
    then \sqrt{2}=\frac{4}{3}(1-x^{2}}^{\frac{-1}{2}}
    You simply need to replace (1-x^{2}}^{\frac{-1}{-2}} with your expansion and set x=\frac{1}{3}
    thank you thankyou. however i tried replacing it, it didn't work out. i will try again.
 
 
 
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