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    (Original post by hajira)
    heehee
    wat was the distance it was travelling down the slope?
    my mind has blanked out to the answer to that last bit..im gona work it out like i did in exam!
    8....
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    how many marks do we loss if we get the CoM (a) wrong, is that any E.C.F for part (b)?
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    (Original post by topdude)
    i think the only marks i lost was the 6c 1, where it goes prove theres only a horizontal force, and maybe the COM one, where i got 31/11 (althou i think that its right)
    31/11 is wrong mate. sorry to tell you. the answer was a nice round 3.
    you should get some method marks though
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    (Original post by im37)
    how many marks do we loss if we get the CoM (a) wrong, is that any E.C.F for part (b)?
    i think CoM (a) was 5 marks. depends on what you did wrong (ie if you took as a lamina, prob lose accuracy marks). and for part (b) there will definetly be follow through marks
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    (Original post by topdude)
    8....
    n wat was the angle?
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    (Original post by hajira)
    n wat was the angle?
    30
    HENCE my method of 8sin30x3xg
    lol
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    (Original post by Zuber)
    30
    HENCE my method of 8sin30x3xg
    lol
    heheh..it might b a good idea to ignore me, im jus not thinkin rite now am i :rolleyes:

    that paper was easy
    we all did fine
    im jus annoyed at that arithmetic mistake :mad:

    o well :rolleyes: time to go to bed
    adios

    ps: never b an idealist!
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    sadly i took it as lamina, but the following method marks r the same~ so i lost perhaps 1-2 marks there!?
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    btw for 3b) where it asked for acceleration, i got -36i +8j but i also found magnitude in case. it was odd that they didnt specify....
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    (Original post by im37)
    sadly i took it as lamina, but the following method marks r the same~ so i lost perhaps 1-2 marks there!?
    yeah, i think max losing =2marks
    i too made a silly mistake (read higher up this thread). i accidentally used mass of B=3 instead of 2. (for 5b ). dont worry. if we lose only 2 marks (or 1) we might still get 100
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    this M2 paper is fair~ i guess 70/75 will be full mark rt? (taking account into UMS)
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    To sum up then
    1)a)35 [3]
    b)14.6 [4]
    2a)31/11 [5]-- however sum people got 3 which is right?
    b)15/77 [3]-- and using three they got 1/7 which is right
    3a)c=4 [6]
    b) -36i + 8j [3]
    4a) 1.8m[5]
    b)6.75[5]
    5a) 2/3 [7]
    b) proof [7]
    6a) i got 1018.4 and no1 has added here [4]
    b) i got 770ish and agen no1 has added here [6]
    c) proof [2]
    7a)117.6J[2]
    b) 10N[5]
    c) 0.393[3]
    d) 5.4 [5]
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    (Original post by simiddd)
    To sum up then
    1)a)35 [3]
    b)14.6 [4]
    2a)31/11 [5]-- however sum people got 3 which is right?
    b)15/77 [3]-- and using three they got 1/7 which is right
    3a)c=4 [6]
    b) -36i + 8j [3]
    4a) 1.8m[5]
    b)6.75[5]
    5a) 2/3 [7]
    b) proof [7]
    6a) i got 1018.4 and no1 has added here [4]
    b) i got 770ish and agen no1 has added here [6]
    c) proof [2]
    7a)117.6J[2]
    b) 10N[5]
    c) 0.393[3]
    d) 5.4 [5]
    2a) 3, b)k=1/7
    6b) 778N (3sf)
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    (Original post by im37)
    this M2 paper is fair~ i guess 70/75 will be full mark rt? (taking account into UMS)
    i have no idea. i hope so. i did 1 stupid mistake. everything else so far seems to be correct
    i would guess about 72 would be full marks.....but that is just a random guess. not sure how edexcel measure what is 100
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    (Original post by simiddd)
    To sum up then
    2a)31/11 [5]-- however sum people got 3 which is right?
    b)15/77 [3]-- and using three they got 1/7 which is right

    3b) -36i + 8j [3]

    7d) 5.4 [5]
    I disagree with the above:

    2a) 3cm
    b) 1/7

    3b) They wanted accelleration, so i'm guessing not the vector... so: 36.9ms-2

    7d) 5.93ms-1 5.39 ms-1


    Someone please confirm...
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    (Original post by ArVi)
    I disagree with the above:

    2a) 3cm
    b) 1/7

    3b) They wanted accelleration, so i'm guessing not the vector... so: 36.9ms-2

    7d) 5.93ms-1


    Someone please confirm...
    agree with all except 7d) it was 5.39ms-1
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    I disagree with the above:

    2a) 3cm
    b) 1/7

    3b) They wanted accelleration, so i'm guessing not the vector... so: 36.9ms-2

    7d) 5.93ms-1
    For 3b i wasnt sure wht they wanted so i put both the vector and the magnitude for the acceleration..so i'll get the mark for either
    i cant remmber 7b and i made the same mistake for q3 took it as a square and a triangle ...how much do u reckon i wud gt by follow thru?
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    (Original post by mysterious_grl)
    For 3b i wasnt sure wht they wanted so i put both the vector and the magnitude for the acceleration..so i'll get the mark for either
    i cant remmber 7b and i made the same mistake for q3 took it as a square and a triangle ...how much do u reckon i wud gt by follow thru?
    for q3, it was worth 5, so i think you might get about 3 for method...
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    (Original post by ArVi)


    3b) They wanted accelleration, so i'm guessing not the vector... so: 36.9ms-2




    Someone please confirm...
    acceleration is a vector .
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    (Original post by Mathemagician)
    acceleration is a vector .
    true
    i left both...wasnt sure
 
 
 
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