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    for the proof only horizontal force thing, I found the new thrust & resolved vertically. I got Vertical component of the Force 0. That means it only works horizontally. Do u guys think that it is alrite?
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    Oh I wish someone could post the paper
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    (Original post by im37)
    for the proof only horizontal force thing, I found the new thrust & resolved vertically. I got Vertical component of the Force 0. That means it only works horizontally. Do u guys think that it is alrite?
    thats what i did!!! it should be fine - we still answered the question (in a different way than was intended).
    the new thrust was 60g and the angle between thrust and vertical was 60°, right?
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    lol.. i know accelleration is a vector.

    its just that when they want the answer in vector form they say "find the accelleration vector". Anyway i had to find the vector before finding |a| so i guess either way i'm safe (i hope)
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    (Original post by ArVi)
    lol.. i know accelleration is a vector.

    its just that when they want the answer in vector form they say "find the accelleration vector". Anyway i had to find the vector before finding |a| so i guess either way i'm safe (i hope)
    yeah if you have both you are definetly fine. covering your bases is always a wise choice
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    I want KAISER_MOLE's answer.
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    (Original post by ArVi)
    I disagree with the above:

    2a) 3cm
    b) 1/7

    3b) They wanted accelleration, so i'm guessing not the vector... so: 36.9ms-2

    7d) 5.93ms-1


    Someone please confirm...
    Sorry: 5.39 ms-1 is correct (√29)
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    *sigh*....no more maths!
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    (Original post by Mathemagician)
    *sigh*....no more maths!
    C4 still for me
    and for others, P4
    both on tuesday pm
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    yeh i got the ones mentioned wrong but are the others right?
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    (Original post by im37)
    for the proof only horizontal force thing, I found the new thrust & resolved vertically. I got Vertical component of the Force 0. That means it only works horizontally. Do u guys think that it is alrite?

    I did the same and got 60 degrees too. How were we supposed to do it?
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    i hate mechanics! thats all i have to say!!
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    (Original post by riddles55)
    I did the same and got 60 degrees too. How were we supposed to do it?
    i did the same, but i was told (and realised straight away) that all that working out is not needed
    all you need to do is take moments from the midpoint of AB (hence thrust and weight have no effects) and so at A there would be no vertical component
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    (Original post by microwave69)
    i hate mechanics! thats all i have to say!!
    OI :mad: mechanics is pure beauty . if you cant see that it is because you are not worthy enough :cool:
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    btw slightly off topic, the examiners, do they get the mark schemes that we get? i.e. like the mark schemes that i have for previous papers - that only shows the right answer and method?
    anyone know anything about the marking process?
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    ahhhh... lol, i did about half a page with trig etc just to work that out! How were we supposed to spot the moments thing! I need more clues!
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    (Original post by riddles55)
    ahhhh... lol, i did about half a page with trig etc just to work that out! How were we supposed to spot the moments thing! I need more clues!
    i took half a page but tahts cos i always show all steps in exam for marker. not too much space was needed. here's my method so you lot can compare:

    finding angle (use previous situation to find the length of AC)
    AC/sin60 = 0.5/sin30
    AC = √3/2
    tanx = 1.5/AC = 1.5/(√3/2) = √3
    x = 60°

    then take moments around A:
    ACsin60 x T = 1.5x30g
    3/4T= 45g
    T= 60g

    then just resolve vertically (where R is the vertical force exerted by wall on point A):
    Tcos60 - 30g - R=0
    R = 60gx0.5 - 30g
    R = 0

    hence at A, there is no vertical force!


    .........not bad for a 2marker
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    Hi there, i noticed an answer thread for M1 and looked like a good idea cos i dont like waiting til August for my results, but i couldnt actually remember what Id put for each one - so today I thought Id write all my answers down in my calculator lid... Id much appreciate it if someone could have a quick look through and give me a mark/tell me which ones are wrong...

    1a) 35m/s
    b) 14.6m/s

    2a) 3cm
    b) k=1/7

    3a) 4
    b) 36.9m/s/s

    4a) 1.8m
    b) 6.75

    5a) e=2/3
    b) Some proof that the speed of B after its collision with C is less than that of A after its collision with B

    6a) 1018N
    b) 778N
    c) Some proof that the vertical component is zero because Tcos(angle)= 30g

    7a) 117.6J
    b) 10.0N
    c) coeff fric = 0.393
    d) 5.39m/s

    Thanks everyone
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    (Original post by andyd_y02)
    Hi there, i noticed an answer thread for M1 and looked like a good idea cos i dont like waiting til August for my results, but i couldnt actually remember what Id put for each one - so today I thought Id write all my answers down in my calculator lid... Id much appreciate it if someone could have a quick look through and give me a mark/tell me which ones are wrong...

    1a) 35m/s
    b) 14.6m/s

    2a) 3cm
    b) k=1/7

    3a) 4
    b) 36.9m/s/s

    4a) 1.8m
    b) 6.75

    5a) e=2/3
    b) Some proof that the speed of B after its collision with C is less than that of A after its collision with B

    6a) 1018N
    b) 778N
    c) Some proof that the vertical component is zero because Tcos(angle)= 30g

    7a) 117.6J
    b) 10.0N
    c) coeff fric = 0.393
    d) 5.39m/s

    Thanks everyone
    All right mate. well done
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    Cheers mate - il prob need about full marks - i havnt got a "TSR grade" for p3 but im pretty that was C or below! so even with good mark on M2 its going to be a close run thing...
 
 
 
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