P6 Vectors

This is the question in June 03:
7) The plane π passes through the point P, with position vector i + 2j - k, and is perpendicular to the line L with equation

r = 3i - 2k + λ(-1 + 2j + 3k)

a) Show that the Cartesian equation of π is x - 5y - 3z = -6

I think there "might" be a problem with the question itself:

should the line L say:

r = 3i - 2k + λ(-1 + 5j + 3k)?

Thanks so much.

Reply 1

Gaz031

15

darkenergy

This is the question in June 03:
7) The plane π passes through the point P, with position vector i + 2j - k, and is perpendicular to the line L with equation

r = 3i - 2k + λ(-1 + 2j + 3k)

a) Show that the Cartesian equation of π is x - 5y - 3z = -6

I think there "might" be a problem with the question itself:

should the line L say:

r = 3i - 2k + λ(-1 + 5j + 3k)?

Thanks so much.

I'm fairly sure your alteration is correct as -i+2j+3k is certainly not parallel to i-5j-3k whereas yours is.

Reply 2

Comp_Genius

OP

4

Thanks very much, i was panicking :frown:

its from one of the papers on this site!? Did they make the same mistake in the real paper?

Reply 3

Gaz031

15

darkenergy

Thanks very much, i was panicking :frown:

its from one of the papers on this site!? Did they make the same mistake in the real paper?

I'm not sure whether the mistake was made in the real paper but I wouldn't have thought so. Perhaps it was a scanning or typing error when someone copied the paper onto their computer to put it on the internet.
If it had been on the real paper then a notice would have been sent out for candidates to correct it.

OP

oh rite

i have the real ppr n it is wrong i think!! ¬.¬

P6 Vectors

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