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area between the curve...

for this question do I just integrate y from -pi to pi?

i.e.
Unparseable latex formula:

\displaystyle \int_a^b \ { e^-^x sin2x } dx




where a=−π a =-\pi and b=π b =\pi

??1.doc
Reply 1
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It doesnt want any negative area...so you will have to find the points where it crosses the x axis (between -pi and pi) and integrate accordingly.
refref
It doesnt want any negative area...so you will have to find the points where it crosses the x axis (between -pi and pi) and integrate accordingly.


and how do i go about doing that?
Reply 3
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e^(-x)sin(2x) = 0

e(-x) is never 0, so make sin(2x) = 0, find the values of x in the range -pi ~ pi.

so for positive values of x, x = pi/2, pi

integrate between 0 and pi/2, and between pi/2 and pi. Add these 'areas' up (one of them will be negative, so change it to positive).

Do the same for negative x.

I think this is right...

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