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    Ok, solve the equation

    y²+5y - (36/y²+5y) = 0

    OK, so its pretty obvious that we make t = y²+5 therefore giving us...

    t - 36/t = 0

    Then i multiplied through by t giving

    t² - 36 = 0

    Then from here I said
    t²=36
    obviously therefore t = √36 = 6

    from here i get.... y²+5y-6 = 0 giving me the results ..
    (y+1) (y-6)
    y = -1 y = + 6

    The question is what do i do now, i'm sure there are more answers than that?
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    t= \pm 6
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    (Original post by Gaz031)
    t= \pm 6
    Giving: y²+5y+6 = 0

    (y + 3)(y + 2) = 0

    y = -3, y = -2
 
 
 
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Updated: June 26, 2005
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