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# Mechanics SHM watch

1. How does the angle of release affect the time period of a pendulum and why does it affect it so?
2. (Original post by MC REN)
How does the angle of release affect the time period of a pendulum and why does it affect it so?
The greater the release angle, the greater the period of oscillation of pendulum.
Due to greater gain in kinetic potential energy.
3. (Original post by Vijay1)
The greater the release angle, the greater the period of oscillation of pendulum.
Due to greater gain in kinetic potential energy.
well actually the period doesnt change if the angle is changed (as long as the angle is small)!
the period of the pendulum is 2pi rt[l/g] ... i.e. it's independant of @
4. (Original post by yazan_l)
well actually the period doesnt change if the angle is changed!
the period of the pendulum is 2pi rt[l/g] ... i.e. it's independant of @
Well, I've not yet studied Mechanics, and was expecting someone to correct my very basic interpretation of a pendulum in motion.
5. it is only independent when the angle is fairly small, greater than say 15' it affects it, apparently
6. (Original post by MC REN)
it is only independent when the angle is fairly small, greater than say 15' it affects it, apparently
Obviously
7. see my EDITED post: i say that there! if u were asking about when the angle is not small, then it's not even SHM!
8. (Original post by Vijay1)
The greater the release angle, the greater the period of oscillation of pendulum.
Due to greater gain in kinetic potential energy.
greater gain in ke --> greater gain in speed --> shorter time period --> the increase in time period is due to the increase in distance travelled

where is the flaw in this argument?
9. (Original post by yazan_l)
see my EDITED post: i say that there! if u were asking about when the angle is not small, then it's not even SHM!
oh k, i haven't been in any lessons yet, just had to do an experiment and write an investigation for this week so i'm trying to get it sorted out

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