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    Hi, i need some help on the maths coursework emmas dilemma. If anyone has done it could they help me with any formula ect????
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    (Original post by childe)
    Hi, i need some help on the maths coursework emmas dilemma. If anyone has done it could they help me with any formula ect????
    i did this for gcse.its not that bad once you've got the idea.you need to look up factorials and permutations.i.e. 2! = 2 x 1 and 3! = 3 x 2 x 1

    Also, you need to consider whether letters are repeated in the word you're trying to do. Emma only has 3 different letters whereas Lucy has 4 different letters, so the number of permutations of the words will be different as well.

    Its a long time since I did it (nearly 3 years ago now) but i'll try and remember if u need any more help
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    (Original post by Jessie)
    i did this for gcse.its not that bad once you've got the idea.you need to look up factorials and permutations.i.e. 2! = 2 x 1 and 3! = 3 x 2 x 1

    Also, you need to consider whether letters are repeated in the word you're trying to do. Emma only has 3 different letters whereas Lucy has 4 different letters, so the number of permutations of the words will be different as well.

    Its a long time since I did it (nearly 3 years ago now) but i'll try and remember if u need any more help
    i knew that :rolleyes:
 
 
 
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