The Student Room Group
Reply 1
2x3x2+x2 2x^3-x^2+x-2

I presume you mean that.

For first bit put f(1) in. 2(1)-(1)+1-2=0 therefore x-1 is a factor. And then as it says use long division that you've been taught with (x-1)/(2x^3-x^2+x-2) and you'll get a quadratic and then factorise that for the other two factors
Reply 2
Plug in (1) as the x-value (its always the opposite sign). Next think of numbers that multiply to make -2. The other factor has to be x-2, so factorised it is (x-1) (x-1) (x-2)
Reply 3
Is long division compulsory for C1? We just skipped it and used the Remainder Theorem :/
Reply 4
deco2009
f(x) = 2x and little 3 on top - x^ + x - 2

Brilliant.

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