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# trapezium rule C2 watch

1. I know how to do it, with normal ranges but this one includes pie,

5 ordinate,

pie/2

to 0

Square root of (1+sinx)
(I know i need to us radians on this)

How do i find the values between 0 and pie/2?

The mark scheme uses:

0
pie/8
pie/4
3pie/8
pie/2

How did they get those values in the middle?
I know normally if its between 0 and 0.4 its just
0
0.1
0.3
0.3
0.4

How can i do this with Pie?
Thanks.
2. Pi is a number just like any other. If it helps, think of 1/2 - you would split it up into 0, 1/8, 1/4, 3/8, 1/2. Same situation here, just scaled by a factor of pi.
3. Urgh hate this
4. Me too ^

Sorry, i still don't understand.

I tried dividing pie/2 by 1/2 but its no good.
How do i find the values between 0 and pie/2?
Sorry if im being a dumbass!
5. Are you using pi as radians pi? That will make a difference.

h=(b-a)/n = ((pi/2)-0)/5 = pi/10

Then do the trapezium stuff.
6. im using it as radians when i come to insert the x values because its the function is SIN and it requires my calc to be in radians doesnt it?
7. well the first value would be 0 and the last one would be pi/2... so the third one (middle) would be pi/4, the second would thus be pi/8 and the forth would be pi/8 +pi/4 = 3pi/8
so;
x=o
x=pi/8
x=pi/4
x=3pi/8
x=pi/2

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