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    • Thread Starter
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    I know how to do it, with normal ranges but this one includes pie,

    5 ordinate,

    pie/2

    to 0

    Square root of (1+sinx)
    (I know i need to us radians on this)

    How do i find the values between 0 and pie/2?

    The mark scheme uses:

    0
    pie/8
    pie/4
    3pie/8
    pie/2

    How did they get those values in the middle?
    I know normally if its between 0 and 0.4 its just
    0
    0.1
    0.3
    0.3
    0.4

    How can i do this with Pie?
    Thanks.
    • Wiki Support Team
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    Wiki Support Team
    Pi is a number just like any other. If it helps, think of 1/2 - you would split it up into 0, 1/8, 1/4, 3/8, 1/2. Same situation here, just scaled by a factor of pi.
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    Urgh hate this
    • Thread Starter
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    Me too ^

    Sorry, i still don't understand.

    I tried dividing pie/2 by 1/2 but its no good.
    How do i find the values between 0 and pie/2?
    Sorry if im being a dumbass!
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    Are you using pi as radians pi? That will make a difference.

    h=(b-a)/n = ((pi/2)-0)/5 = pi/10

    Then do the trapezium stuff.
    • Thread Starter
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    im using it as radians when i come to insert the x values because its the function is SIN and it requires my calc to be in radians doesnt it?
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    well the first value would be 0 and the last one would be pi/2... so the third one (middle) would be pi/4, the second would thus be pi/8 and the forth would be pi/8 +pi/4 = 3pi/8
    so;
    x=o
    x=pi/8
    x=pi/4
    x=3pi/8
    x=pi/2
 
 
 
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