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    does anyone know the reason why this is...

    y=/x/ (modulus of x)
    translation by [4,0] then stretch by sf 2 in the x-direction looks lyk this..
    y= 1/2 /x-4/?

    and if do the transformation in the opposite order it looks like this...
    y= /0.5x - 2/

    :O
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    (Original post by kesh_888)
    does anyone know the reason why this is...

    y=/x/ (modulus of x)
    translation by [4,0] then stretch by sf 2 in the x-direction looks lyk this..
    y= 1/2 /x-4/?

    and if do the transformation in the opposite order it looks like this...
    y= /0.5x - 2/

    :O
    I suggest you post the original question.
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    show that the image of y=/x/ (modulus of x) after a
    translation by [4,0] followed bya stretch by sf 2 in the x-direction looks lyk y= /o.5 x-4/?

    now find the image of y=/x/ after applying the same transformation in the opposte order?

    i dnt get how the order works?
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    (Original post by kesh_888)
    show that the image of y=/x/ (modulus of x) after a
    translation by [4,0] followed bya stretch by sf 2 in the x-direction looks lyk y= /o.5 x-4/?

    now find the image of y=/x/ after applying the same transformation in the opposte order?

    i dnt get how the order works?
    Why are you spelling "like" in a strange way?

    Why have you omitted brackets?

    Where does the question come from?
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    x always goes first
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    im typing really fast thats why. its not brackets its a modulus function but i dont know how to get the straight line on the computer.
    its from the 'Cambrigde SMP AS/A2 mathematics AQA' book
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    (Original post by kesh_888)
    im typing really fast thats why. its not brackets its a modulus function but i dont know how to get the straight line on the computer.
    its from the 'Cambrigde SMP AS/A2 mathematics AQA' book
    You should have put brackets around the x-4

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    oh right i get it now! thanks
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    so if it says s stretch first, do i do fill in the stretch ( y=x strech by sf 2>>>>> y=1/2x) and then if it says followed by translation (4,0), do i put the x and 4 in a bracket? >>> y= 1/2(x-4)??

    if its the other way round is it...
    y= (x-4) then y=(1/2x -4) ??
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    (Original post by kesh_888)
    show that the image of y=/x/ (modulus of x) after a
    translation by [4,0] followed bya stretch by sf 2 in the x-direction looks lyk y= /o.5 x-4/?

    now find the image of y=/x/ after applying the same transformation in the opposte order?

    i dnt get how the order works?

    y=/x/

    translation

    y=/x-4/

    stretch

    y=/ x/2-4 /
 
 
 
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