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    what conditions are reagents do you need to go from:

    ch3cooh -----> (ch3coo)2Mg

    and

    ch3ch2oh ---> ch3ch2o+na-
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    For the first one, 2CH3COOH + Mg(OH)2 ----> (CH3COO^-)2Mg^+ + 2H2O, think it's just room temp and pressure?

    For the second, CH3CH2OOH + NaOH ----> CH3CH2O^-Na^+ + H2O, room temp and pressure.

    EDIT: Ignore :p:
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    You're taking an acid and forming its salt so you need to react the acid with any base really, which contains Na+ or Mg2+. As long as the base is strong enough to deprotonate ethanoic acid. Either NaOH / Mg(OH)2 (as in the post above) or Na2(CO3) / MgCO3 should do it.
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    Adding magnesium/sodium metal should do the trick too :yep:
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    (Original post by Kyri)
    You're taking an acid and forming its salt so you need to react the acid with any base really, which contains Na+ or Mg2+. As long as the base is strong enough to deprotonate ethanoic acid. Either NaOH / Mg(OH)2 (as in the post above) or Na2(CO3) / MgCO3 should do it.
    The second one is an alcohol, i didnt think alcohols reacted with hydroxides or carbonates at room temp?
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    (Original post by LearningMath)
    The second one is an alcohol, i didnt think alcohols reacted with hydroxides or carbonates at room temp?
    Lol, it seems I made exactly the same mistake as you did :p:. Seeing as the first one is carboxylic acid, at first glance the second one looks like a carboxylic acid too.
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    (Original post by Kyri)
    Lol, it seems I made exactly the same mistake as you did :p:. Seeing as the first one is carboxylic acid, at first glance the second one looks like a carboxylic acid too.
    :five:
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    Which exam board?
 
 
 
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