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# Last Minute M1 Question! watch

1. In a simple model of the motion of a car, its velocity vm/s, at time t seconds is given by

v= (3t^2 -4t +1)i + (5t- 3)j where t is greater than or equal to 0

a) Find the intial speed of the car.

b) Find when the car is moving parallel to the vector (i - j)
2. omg i have no idea
u dont have enough to do suvat do you?
3. Wouldnt you put t=0 to find initial speed?

And then put your v equation equal to (i-j) to find t when moving parallel?

Im just guessing =/
Oh god, ive got this soon aswell =/
4. I guess it starts at t=0

t=0

i - 3j = initial velocity

Initial speed = square root 1^2 + 3^2 = square root of 10

For parallel to (i - j)

Velocity will be xi - xj

3t^2 -4t +1 = -5t +3

3t^2 + t -2 = 0

3t^2 +3t -2t -2 = 0

(3t -2) (t + 1) = 0

so T = 2/3 or t = -1

I think????

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Updated: January 15, 2010
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