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    Can someone explain to me where the implication, 'therefore p is not a Gaussian prime' comes from?
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    In a ring, the definition of a prime p is:

    p is a prime if p is non-zero and non-unit and whenever p | ab, either p | a or p | b (or both).

    See http://en.wikipedia.org/wiki/Prime_e...cible_elements
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    (Original post by DFranklin)
    In a ring, the definition of a prime p is:

    p is a prime if p is non-zero and non-unit and whenever p | ab, either p | a or p | b (or both).

    See http://en.wikipedia.org/wiki/Prime_e...cible_elements
    Thank you.

    I have no idea why I didn't get it before. All I had to do was look at the definition of a Gaussian prime!
 
 
 
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Updated: January 15, 2010
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