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# Ocr (not Mei) Core 2 Answers January 2010 watch

1. crap i just realised i got very different answers for 6. i got a=15 and b=32.
when I substituted these values back in i got the correct answers
did anybody else get that?
2. (Original post by JChoudhry)
pm me with email, i'll try to scan it in likie 10min or so
can you type out question 5 pleaseeee? or anyone else who knows how to do it.
thank you!
3. I also got x as -2/3. Im sure the point was (p,5) because after factorising i found x to be -2/3 or 2. pOint A was (2, something) and so p as (-2/3) would fit whereas x = 5 wouldnt?
4. (Original post by HotCoco.)
Thanks Mr M. Your very fast!
Collected paper at 15:25 and answers were posted at 15:56 so I was superspeedy (I used a computer for the binomial expansion and the trapezium rule though so I cheated slightly).
5. (Original post by Haruhi)
Mr M, for question 8 iv do I get any method marks for substituting in the arithmetic sum formulae instead of both sigma signs and also sumstituting in values of a and d? even though I got the answer completely wrong?

EDIT: Drive safely!... Im always too slow on things -___-;
You should get at least a couple of marks for that.
6. (Original post by jkkk32)
DAMN! so all you were meant to do was put 5 in? ARGH! lol i must have read it as (P,5) or something gargh lol

the co-ordinate was (P,5), not (5,P), you put y as 5 and solve with quadratic equation, so p = 2. defo!
7. Could someone explain 5 please??
8. (Original post by owen4567)
I also got x as -2/3. Im sure the point was (p,5) because after factorising i found x to be -2/3 or 2. pOint A was (2, something) and so p as (-2/3) would fit whereas x = 5 wouldnt?
your right. i just looked at the paper.
I also got p as this, there is no way on earth it can be 56 surely, -2/3 gave me the right answer when i substituted it back in
How embarrassing for me. -2/3 is correct. I don't know the difference between y and x.
10. (Original post by Mr M)
How embarrassing for me. -2/3 is correct. I don't know the difference between y and x.
was it -2/3 then not 2? 2 seems to fit, giving a yvalue of 5? thank you! i will have got some marks even if it was -2/3 as i had that written down as my other value. thank you
11. (Original post by JChoudhry)
i combined the 2 curves then integrated, then substituted 1 and 3 and hoped to hell it was right but it gave me 5 1/3 so lets hope so
sorry i meant you sub in x=5, and the question was find P when (5,P)!
It was (p,5) not (5,p) so -2/3 is correct.
13. what was question 5 again? what were the equations of the curves? and x values where they intersected each other?
14. (Original post by Mr M)
It was (p,5) not (5,p) so -2/3 is correct.
yeah i know so why is 2 wrong?
15. 5 = 3x^2 - 4x + 1
3x^2 - 4x - 4 = 0
(3x+2) (x-2)
3x+2=0
x = -2/3
and x = 2??
thats what i posted earlier, 2would work though??
16. (Original post by mrdude)
It's positive and not negative because a negative number raised to the 6 is positive.
No the power of 6 comes from so the answer is negative.
17. (Original post by rubberdam123)
what was question 5 again? what were the equations of the curves? and x values where they intersected each other?
y=x^2+1 and y=11-(9/x^2)
intersect at 3 and 1
18. (Original post by JChoudhry)
y=x^2+1 and y=11-(9/x^2)
intersect at 3 and 1
Thanks.
19. -2/3 wouldnt work? but 2 would! can someone confirm this or am i calculate illiterate
20. (Original post by jkkk32)
can you type out question 5 pleaseeee? or anyone else who knows how to do it.
thank you!

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