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    (Original post by jkkk32)
    5 = 3x^2 - 4x + 1
    3x^2 - 4x - 4 = 0
    (3x+2) (x-2)
    3x+2=0
    x = -2/3
    and x = 2??
    thats what i posted earlier, 2would work though??
    2 is wrong as the point you were given (2, 5) and you were told to find the other one where y = 5.
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    (Original post by jkkk32)
    -2/3 wouldnt work? but 2 would! can someone confirm this or am i calculate illiterate
    I thought this too. But i think it had to be -2/3 because the x coordinate of the other one was 2.
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    (Original post by rubberdam123)
    the co-ordinate was (P,5), not (5,P), you put y as 5 and solve with quadratic equation, so p = 2. defo!
    Undefo sadly!
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    ok thanks
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    (Original post by Mr M)
    \int^3_1 ((11 - 9x^{-2}) - (x^2 + 1)) \ dx = \frac{16}{3}
    How were the marks for this arranged? I think I made a simple arithmetic error right in the beginning and that may have caused me the whole answer wrong. Thanks so much Mr M for this! Really appreciate you doing this.
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    (Original post by JChoudhry)
    How were the marks for this arranged? I think I made a simple arithmetic error right in the beginning and that may have caused me the whole answer wrong. Thanks so much Mr M for this! Really appreciate you doing this.
    One mark for integrating between 1 and 3.

    Two marks for correctly integrating the first curve.

    Two marks for correctly integrating the second curve.

    Two marks for subtracting them (either before or after the integration).
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    has anyone got the question paper?
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    (Original post by mrdude)
    crap i just realised i got very different answers for 6. i got a=15 and b=32.
    when I substituted these values back in i got the correct answers :confused:
    did anybody else get that?
    please tell me somebody else got this? don't wanna throw away 6 easy marks and possibly say goodbye to an A
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    (Original post by Mr M)
    Collected paper at 15:25 and answers were posted at 15:56 so I was superspeedy (I used a computer for the binomial expansion and the trapezium rule though so I cheated slightly).
    Woah, Mr.M. You're something of a Ferrari! Also thanks for the answers

    It looks like I got full marks, (or close to- I can't remember what I said for some Qs)
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    Mr M. can you do the last question, the logs one, i started the question, but I couldnt prove it.
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    (Original post by mrdude)
    please tell me somebody else got this? don't wanna throw away 6 easy marks and possibly say goodbye to an A
    No they are wrong I'm afraid. You might get method marks. What did you do?
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    (Original post by Mr M)
    No they are wrong I'm afraid. You might get method marks. What did you do?
    agh I'm trying to remember the question. I know I entered in the factors given and got two simultaneous equations and from there found the values of a and b. Must've just made a silly mistake somewhere along the way and not noticed. So, because I used the right method, how many marks would I get for that?
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    (Original post by Mr M)
    Undefo sadly!

    what I don't understand is

    there was p = -2/3 and p=2

    both work when you put in equation, which one is right? and how would you know?
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    if you use pascals triangle on the coefficient question you get 35 x 2^4 x (-1/4)^3 = -35/4
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    (Original post by crazyness)
    what I don't understand is

    there was p = -2/3 and p=2

    both work when you put in equation, which one is right? and how would you know?
    you were already given that (2,5) is on the curve, therefore p must equal -2/3
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    (Original post by crazyness)
    Mr M. can you do the last question, the logs one, i started the question, but I couldnt prove it.
    \log_3 9 = 2

    \log_3 6 = 1 + \log_3 2

    y=9^x

    y=6 \times 5^x

    9^x = 6 \times 5^x

    \log_3 9^x = \log_3 (6 \times 5^x)

    x \log_3 9 = \log_3 6 + x \log_3 5

    2x = 1 + \log_3 2 + x \log_3 5

    x(2 - \log_3 5) = 1 + \log_3 2

    x = \frac{1 + \log_3 2}{2 - \log_3 5}
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    (Original post by crazyness)
    what I don't understand is

    there was p = -2/3 and p=2

    both work when you put in equation, which one is right? and how would you know?
    I explained this a few posts ago. p = 2 was given in the question and they asked you to find another "distinct point".
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    (Original post by mrdude)
    you were already given that (2,5) is on the curve, therefore p must equal -2/3
    I left it as p = 2 or p = -2/3 :eek:
    would i get any marks?
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    (Original post by mrdude)
    agh I'm trying to remember the question. I know I entered in the factors given and got two simultaneous equations and from there found the values of a and b. Must've just made a silly mistake somewhere along the way and not noticed. So, because I used the right method, how many marks would I get for that?
    You might get as many as 4 out of 6.
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    (Original post by crazyness)
    I left it as p = 2 or p = -2/3 :eek:
    would i get any marks?
    2 out of 3 (you might even get all 3 if the mark scheme is generous).
 
 
 
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