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    (Original post by Mr M)
    You might get as many as 4 out of 6.
    cool, I should still get an A then. Thanks for all the help Mr M, much appreciated.

    Anybody know when January results come out?
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    will it be around 59/60 for an A in this paper Mr M?
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    (Original post by mrdude)
    cool, I should still get an A then. Thanks for all the help Mr M, much appreciated.

    Anybody know when January results come out?
    Electronically on 11th March.
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    (Original post by crazyness)
    will it be around 59/60 for an A in this paper Mr M?
    I wouldn't like to guess. Just wait and see.
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    (Original post by insertusername)
    yeh you did do this so you had

    N(16 +(2N-1)x3) - 1/2N(16+(N-1)x3)=1256

    N(16 + 6N-3) - 1/2N(16 +3N-3) =1256 then multiply by 2 to make life easier

    2N(13+6N) - N(13+3N)=2512

    12N^2 +26N - 3N^2 +13N =2512

    9N^2 + 13N = 2512

    then i had to use the quadratic formula
    Ok I did this and then stupidly did the quadratic equation wrong. How many marks do you think it is up till this point ?
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    Hey Mr M thankyou so much for the answers

    i have only made two errors and i was wondering what you think i mite be awarded out of them...

    on the coeffeciant of the binomial expansion i put the answer what u have but i cant remember if i put the minus sign? does tht matter? i write out the expansion showing it was minus in my working.

    also in relation to the trapizium rule part 2 question i stupidly multiplied the answer by 2 not by a half altho i did write out the log rule for powers would i get a mark for tht?
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    great, just **** ing great, FML Book me in for resit again, this paper was nothing like past papers. ****
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    (Original post by Mr M)
    One mark for integrating between 1 and 3.

    Two marks for correctly integrating the first curve.

    Two marks for correctly integrating the second curve.

    Two marks for subtracting them (either before or after the integration).
    would you be able to do the working for question 5 please?
    i think i made it all one equation and then integrated it all, is that totally wrong? could you explain how to do it please? thank you
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    (Original post by jkkk32)
    would you be able to do the working for question 5 please?
    i think i made it all one equation and then integrated it all, is that totally wrong? could you explain how to do it please? thank you
    I showed the integration earlier - look back.
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    I'm sort of glad I got this out the way last year. :woo:

    Fiddly bits and what not.

    Although, this seems like a very good paper. :yep:

    Good luck all.
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    (Original post by Virgil)
    great, just f.u.c.k ing great, FML Book me in for resit again, this paper was nothing like past papers. F.U.C.K


    don't worry, i'm in the same boat :hugs:
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    Question 3ii, was it not 560(-1/4w^2)^3 from 7C3x2^4 in 3i) so the answer would be -140w^6 therefore the coefficent -140
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    (Original post by Mr M)
    I showed the integration earlier - look back.
    if i did something along the lines of:

    x^2 + 1 = 11 - 9/X^2

    10x^2 - 9 - X^4
    integrated that:

    10/3 x^3 - 9x - 1/5 x^5

    then put in 1 and 3 into x there


    is that totally wrong? i presume it is and my whole equation that i integrated was wrong? but just thought id check.

    thanks
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    (Original post by Katherine263)
    Question 3ii, was it not 560(-1/4w^2)^3 from 7C3x2^4 in 3i) so the answer would be -140w^6 therefore the coefficent -140
    i put that too, but looks like its wrong.
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    Oh I know what I did -1/4 needs to be -1/4^3 and 560x-1/64 is -35/4 annoying lol
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    (Original post by jkkk32)
    if i did something along the lines of:

    x^2 + 1 = 11 - 9/X^2

    10x^2 - 9 - X^4
    integrated that:

    10/3 x^3 - 9x - 1/5 x^5

    then put in 1 and 3 into x there


    is that totally wrong? i presume it is and my whole equation that i integrated was wrong? but just thought id check.

    thanks

    Yes I'm afraid that is nonsense.
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    haha i thought as much lol how would you have done it if you were integrating one equation though? rather than the two separately?
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    N(16 +(2N-1)x3) - 1/2N(16+(N-1)x3)=1256

    N(16 + 6N-3) - 1/2N(16 +3N-3) =1256 then multiply by 2 to make life easier

    2N(13+6N) - N(13+3N)=2512

    12N^2 +26N - 3N^2 +13N =2512

    9N^2 + 13N = 2512

    Mr M
    I did all of this but did the quadratic equation wrong. How many marks would i get for getting this far?
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    Was I not meant to get a remainder when doing long division because I swear to god the first part was X-3 is a factor and the long division was x+3....I got a +10 Remainder

    And I did equalty what Viqas I think did
    Would I get any marks
    And I put x = -2/3 or 2 for the top questions
    Would I loose a mark

    And for the trapezium rule part two....square rooting the answer is wrong I guess?
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    (Original post by jkkk32)
    haha i thought as much lol how would you have done it if you were integrating one equation though? rather than the two separately?

    I integrated both the forumlas seperatly and subbed in the values.
    Took one from the toher.
    Managed to get 5.3333....I kept it as a fraction....Just can not remember what it is atm
 
 
 
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