diffrentiation

x^2 - y^3=sin(y) Evaluate Dy/Dx at point (0,0)

im not sure what i have to do here....anyone help?

Move the y^3 across, square root both sides, take dx/dy and find its reciprocal.

Here's a thought: perhaps begin by implicitly differentiating the equation?

Bobifier

Move the y^3 across, square root both sides, take dx/dy and find its reciprocal.

I would be cautious about square-rooting an expression that can take negative values...

Kolya

I would be cautious about square-rooting an expression that can take negative values...

Even if it's value is not negative at the required point?

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