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    x^2 - y^3=sin(y) Evaluate Dy/Dx at point (0,0)

    im not sure what i have to do here....anyone help?
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    Move the y^3 across, square root both sides, take dx/dy and find its reciprocal.
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    Here's a thought: perhaps begin by implicitly differentiating the equation?
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    (Original post by Bobifier)
    Move the y^3 across, square root both sides, take dx/dy and find its reciprocal.
    I would be cautious about square-rooting an expression that can take negative values...
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    (Original post by Kolya)
    I would be cautious about square-rooting an expression that can take negative values...
    Even if it's value is not negative at the required point?
 
 
 
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