Turn on thread page Beta
    • Thread Starter
    Offline

    0
    ReputationRep:
    The Moments Question. W was equal to 280 correct ?
    Offline

    0
    ReputationRep:
    (Original post by malteser12345)
    for the tension of A, the second part of the moments question, i got something like
    (1/6 W -40/30)N.
    it was (1/6W -40/3) that was right because using the fact that moment up = moment down C and A had to equal W+20, so adding C and A you got 5/6W + 1/6W + 100/3 -40/3 = W -60/3 = W-20
    Offline

    0
    ReputationRep:
    (Original post by laez90)
    guys here's what....for the distance question i.e the value of T...it said 'it travels at a constant velocity for T seconds' and not 'upto T seconds'.....so you gotta do like 75-(T+5) for the last triangle....at least that's what i think....this way you get 50 secs and not 55....rest all was ok and i think i rememberr my answers to majority of the questions....lemme know if anyone is interested
    yeah i got 50 too
    Offline

    0
    ReputationRep:
    (Original post by man u)
    wt did ppl get for T in speed time graph
    I got 55

    Also wt did ppl get for the tension of BC

    Wt did ppl get the distance travelled by B in pulleys qs
    i don't think it was 55 seconds. i think the question said it accelerate for 5 seconds, then stays at a constant speed for T. this means the constant was for T seconds, ending at T+5, so T was 50? We need to see a paper and a mark scheme.
    Offline

    0
    ReputationRep:
    Here is what I got:

    Momentum Q:
    I= 18Ns
    m=1.5 kg

    Speed time:
    graph: trapezium
    T=50s

    Moments:
    (a) was a proof
    (b) (W/6 -40/3)N
    (c) W=280N

    Inclined surfaces force question:
    coefficient= 0.5066..... = 0.507
    X=12N

    Vectors!!
    speed = 5km/h
    4got the rest...
    last part of vectors, T=1hr and T=5hrs

    Pulleys:
    k=3
    total distance = 3.969 m

    there was another question.. but i 4got wat it was about
    Offline

    0
    ReputationRep:
    (Original post by onawara)
    Here is what I got:

    Momentum Q:
    I= 18Ns
    m=1.5 kg

    Speed time:
    graph: trapezium
    T=50s

    Moments:
    (a) was a proof
    (b) (W/6 -40/3)N
    (c) W=280N

    Inclined surfaces force question:
    coefficient= 0.5066..... = 0.507
    X=12N

    Vectors!!
    speed = 5km/h
    4got the rest...
    last part of vectors, T=1hr and T=5hrs

    Pulleys:
    k=3
    total distance = 2.205 m

    there was another question.. but i 4got wat it was about
    i dont think the total distance on pulleys is that. you got how far it was off the plane by seeing how far A dropped (because they were equal). you also got how far it moved when both sides were still moving (ie how far it dropped again), and then work out the extra bit. it was like 1.67+1.67+0.2 or something like tht, i got around 3.6m?
    Offline

    0
    ReputationRep:
    (Original post by bibekpd)
    Yeh...T was 55s

    For tension i got 12 N after rounding off

    and the distance in the pulley question i got till where you get 5.3 and then i didn't know what else to do afterwards so I guess its wrong... : /

    anyway what do people think the grade boundaries will be for this paper as it was fairly easy ?
    I think T was 50 as the runner had been running for 5s at the start

    I also got the tension as 12N

    I reckon grade boundaries will be around 63/75 for A, 56 for B
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by PHOLIO)
    I think T was 50 as the runner had been running for 5s at the start

    I also got the tension as 12N

    I reckon grade boundaries will be around 63/75 for A, 56 for B
    I hope not
    Offline

    0
    ReputationRep:
    absol-u-tely!!!
    Offline

    0
    ReputationRep:
    absol-u-tely!!!
    Offline

    0
    ReputationRep:
    Dose anyone know the answer for the last question of the paper (last part of the last question (vectors))??
    Offline

    0
    ReputationRep:
    (Original post by titsmcgee)
    i dont think the total distance on pulleys is that. you got how far it was off the plane by seeing how far A dropped (because they were equal). you also got how far it moved when both sides were still moving (ie how far it dropped again), and then work out the extra bit. it was like 1.67+1.67+0.2 or something like tht, i got around 3.6m?
    i think that the value of W was 40N
    value A ws 1/6 W and C was 8 x A
    so C was 4/3
    so 4/3 plus 1/6 = value B and W = 20N and W
    3/2 = W + 20n
    3/2W -W = 20 n
    1/2 W = 20 n
    W = 40 N
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by Maximus112)
    i think that the value of W was 40N
    value A ws 1/6 W and C was 8 x A
    so C was 4/3
    so 4/3 plus 1/6 = value B and W = 20N and W
    3/2 = W + 20n
    3/2W -W = 20 n
    1/2 W = 20 n
    W = 40 N
    I beg to differ Its 280 N , i revised it with alot of ppl And all said the same. u didnt Put (g)
    Offline

    0
    ReputationRep:
    so what was the maximum height gained by the particle.
    ps. did u have to account for the particle acting under gravity aswel.
    i got around 3. something
    Offline

    0
    ReputationRep:
    (Original post by Bassiouni)
    I beg to differ Its 280 N , i revised it with alot of ppl And all said the same. u didnt Put (g)
    Yup :yes: it surely is 280 N
    Offline

    17
    ReputationRep:
    (Original post by Robbyv)
    To clear up the athlete question i'll try and do it by memory but it may be wrong:

    s=1/2bh + bh + 1/2bh
    500=(1/2 x 8 x 5) + (8T) + (0.5 x 8 x (75 - T - 5)
    500=20 + 8T + 300 - 4T -20
    200=4T
    T=50s

    Thats what i got anyway so ya know
    That's correct according to Arsey.
    Offline

    17
    ReputationRep:
    (Original post by Bassiouni)
    I beg to differ Its 280 N , i revised it with alot of ppl And all said the same. u didnt Put (g)
    That is correct! I feel better about this M1 than June '09s one
    Offline

    17
    ReputationRep:
    (Original post by onawara)
    Here is what I got:

    Momentum Q:
    I= 18Ns
    m=1.5 kg

    Speed time:
    graph: trapezium
    T=50s

    Moments:
    (a) was a proof
    (b) (W/6 -40/3)N
    (c) W=280N

    Inclined surfaces force question:
    coefficient= 0.5066..... = 0.507
    X=12N

    Vectors!!
    speed = 5km/h
    4got the rest...
    last part of vectors, T=1hr and T=5hrs

    Pulleys:
    k=3
    total distance = 2.205 m

    there was another question.. but i 4got wat it was about
    Pulley distance is wrong, I got 2.205 but the weight was alread initially above the ground so the greatest height reached was something different..
    Offline

    0
    ReputationRep:
    so wat is the maximum height of the particle???:confused:
    did any1 actuaaly do it right?
    Offline

    0
    ReputationRep:
    if I get 69/75 in raw mark how much will I get in ums/
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: January 26, 2010

University open days

  1. Norwich University of the Arts
    Postgraduate Open Days Postgraduate
    Thu, 19 Jul '18
  2. University of Sunderland
    Postgraduate Open Day Postgraduate
    Thu, 19 Jul '18
  3. Plymouth College of Art
    All MA Programmes Postgraduate
    Thu, 19 Jul '18
Poll
How are you feeling in the run-up to Results Day 2018?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.