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# The 2010, Honorary Member Welcoming, Undergraduate Degree Results Chat Thread Mk. IV watch

1. I don't get electromagnetic induction at all
2. Hi. I missed my lecture and my lab session. . Now all I have to look forward to today is washing.
3. Good evening
4. anyone know how you integrate e^3x^2/2?

that is, e all to the power of 3x^2 divided by 2.
5. Sub. u = 3x² ?
6. good idea
7. btw, the divided by two is in the power.
8. still like impossible
9. Oh, hmm, try u = x²? When you differentiate you'll get rid of the 2?
10. (Original post by sil3nt_cha0s)
anyone know how you integrate e^3x^2/2?

that is, e all to the power of 3x^2 divided by 2.
Scrap that.

So its

I don;t think it would be right but just differentiate the then use chain rule idea to bring it before e, and after e if yoy get that at all?

We need Max/TTO/jenni
11. (Original post by sil3nt_cha0s)
still like impossible
I just put it in Wolfram and it comes out as something ridiculous.
12. (Original post by Loz17)
Scrap that.

So its

I don;t think it would be right but just differentiate the then use chain rule idea to bring it before e, and after e if yoy get that at all?

We need Max/TTO/jenni
I got 2/3

but then the wrong answer overall. i'll try again
13. (Original post by sil3nt_cha0s)
I got 2/3

but then the wrong answer overall. i'll try again
You could try splitting it up into (e^x²)^(3/2) (can't use Latex )?
14. (Original post by + polarity -)
You could try splitting it up into (e^x²)^(3/2) (can't use Latex )?
I just managed to get the correct answer

was the differential equation dx/dt + 3x = e^-t
15. I've not got as far as using diffential eqs in integration

anyway back yoto work, gonna be late

16. (Original post by sil3nt_cha0s)
I just managed to get the correct answer

was the differential equation dx/dt + 3x = e^-t

bye!
17. (Original post by + polarity -)
oh, I'm still here
18. Hi/

Gonna do my washing soon.

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