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The 2010, Honorary Member Welcoming, Undergraduate Degree Results Chat Thread Mk. IV watch

1. (Original post by Smeh)
At least you'll have something to take your mind off exam results.
If you and A_master actually make it i'll...i'll...hmm what should I do?
you should do FFF too!

or maybe FFM
2. (Original post by dichr0ic)
you should do FFF too!

or maybe FFM

See this is the type of banter I'd be rofling at irl
3. (Original post by dichr0ic)
you should do FFF too!

or maybe FFM

Sounds like fun
4. (Original post by sil3nt_cha0s)
I got from y" + 6y' + 10 = 20

down to

but wolfram says the answer is

why did they divide the last term by 10 and add in a sin and a cos?

Total BS

Well not totally, but you're including t's in there again and that's wrong.

(Original post by sil3nt_cha0s)
how do I do this differential equation: y" + 6y' + 10y = 20

when I get to t^2 + 6t + 10 and it won't factorise how do I do it? no idea
So solve . Have you heard of imaginary numbers??

t= -3+i, -3-i

So this gives the complementary function:

Now you need to find the particular integral. The RHS=20, so we can guess that it is of the form .

Differentiate twice, sub into the original ODE, equate coefficients and solve C/D/E. The general solution = complementary function + particular integral.

Perhaps you should search for an old FP book (FP1 or 2 - I can't remember) or 'An Introduction to Ordinary Differential Equations' by Robinson.

http://opac.warwick.ac.uk/search~S1/i?0521533910

That's the search for it in our library.
5. Check my rad post count
6. (Original post by Loz17)

Sounds like fun

it's the national pastime of sierra leone. i've done a couple.

it's a bit weird though. someone inevitably gets left out.
7. (Original post by dichr0ic)
you should do FFF too!

or maybe FFM

Ok i'll do it.
Just...gimme a few minutes...
8. (Original post by A_master)
999 or your true one of 3164?
9. (Original post by A_master)
You've only made 999 'possibly useful' posts.
10. (Original post by A_master)

11. (Original post by A_master)
well played
12. (Original post by Loz17)
999 or your true one of 3164?
13. (Original post by TheTallOne)
You've only made 999 'possibly useful' posts.
99% of those 999 are not useful
14. (Original post by dichr0ic)

it's the national pastime of sierra leone. i've done a couple.

it's a bit weird though. someone inevitably gets left out.
I wanna go there!

I can imagine.

Spoiler:
Show
I've always wanted to try FFM if I'm honest. Its a fantasy that Toby and I both share but I am pertified of posible consequences
15. (Original post by A_master)
You should see my true post count. 12k+
16. (Original post by Smeh)

Ok i'll do it.
Just...gimme a few minutes...
tbh i think the thread would be prefer it if you waited and did FFM.

sincerely.
17. (Original post by Loz17)
You should see my true post count. 12k+

What a lozer geddit?
18. (Original post by A_master)

What a lozer geddit?
19. (Original post by Loz17)
I wanna go there!

I can imagine.

Spoiler:
Show
I've always wanted to try FFM if I'm honest. Its a fantasy that Toby and I both share but I am pertified of posible consequences
indeed

i've seen many a-thread in h&r (in my short time here ) of boyfriends choosing someone to have a threesome with, then the gf gets totally neglected, it's basically cheating

i think the constituents of the couple should choose together, that way noone gets left behind, noone is left to slip away...
20. (Original post by TheTallOne)
Total BS

Well not totally, but you're including t's in there again and that's wrong.

So solve . Have you heard of imaginary numbers??

t= -3+i, -3-i

So this gives the complementary function:

Now you need to find the particular integral. The RHS=20, so we can guess that it is of the form .

Differentiate twice, sub into the original ODE, equate coefficients and solve C/D/E. The general solution = complementary function + particular integral.

Perhaps you should search for an old FP book (FP1 or 2 - I can't remember) or 'An Introduction to Ordinary Differential Equations' by Robinson.

http://opac.warwick.ac.uk/search~S1/i?0521533910

That's the search for it in our library.

still not getting why it's of the particular form

or why a constant on the right has the particular form of a quadratic...

but E = 2, C = 0 amd D = 0, to give that answer above, + 2

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Updated: February 6, 2010
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