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    I hope this works...



    I don't have a clue what to do :/

    EDIT: SEE FURTHER DOWN
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    I love how tiny that is, give me five mintues...
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    Lol, that's WAY too small to read :/
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    oh balls, this isnt working out well...

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    err... what are a and b?
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    can you please show the full question
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    (Original post by Pheylan)
    err... what are a and b?
    Sorry I'm not doing this too well...
    The graphy shows part of the function y= a ln(bx)
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    (Original post by irish_4_life)
    Sorry I'm not doing this too well...
    The graphy shows part of the function y= a ln(bx)
    oh ok

    y = aln(bx)

    and you have two points it goes through

    0 = aln(2b)
    1 = aln(4b)

    so you can solve these simultaneously

    ln(2b) = 0
    2b = 1
    b = 1/2

    1 = aln(2)
    a = 1/ln(2)
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    (Original post by victor_b1992)
    can you please show the full question
    It's only the top line which is missed off! which i just wrote...
    The graphy shows part of the function y= a ln(bx)
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    ok so
    Aln(2B)=0

    ln(2B)=0 ln(1)=0

    so b=0.5

    then sub b into Aln(4B)=1
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    what exam broad is this
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    (Original post by victor_b1992)
    what exam broad is this
    OCR MEI, thanks for the help
 
 
 
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