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    • Thread Starter


    Sketch the graphs of y= x^2 - 4 and y=/ x^2 - 4/, indicating the points where the graphs meet the x-axis and the y-axis.

    Do those brackets in second equation mean that anything which would be negative on a graph has to be reflected in positive direction?

    And how do I chose values for x...please could anybody help to explain me this, as I really have no idea about doing this questions...we didn`t do a lot about it in college.

    Thank you very much.

    first graph crosses x at 2 at -2 and y at -4.

    second does indeed reflect all negative y to positive.

    ... I think.

    For y= x^2 - 4
    Draw the graph of y=x^2 and shift it vertically by 4 units in the negative direction. (Simple transformation)

    For y=|y= x^2 - 4| means you have to reflect all values of y<0 in the x-axis.

    To find points of intersection with the y-axis let x=0 and solve.
    To find points of intersection with the x-axis let y=0 and solve.
    • Thread Starter

    thanks to both of you
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Updated: January 19, 2010
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