zahir27
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#1
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What mass of iron(II) sulfate would be needed to provide 28 grams of iron?
Remember to give the unit.

Relative atomic masses: O = 16; S = 32; Fe = 56.
Relative formula mass for this FeSO4 = 152

Can some one pls tell me step by step how to do it
thanks =) x
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TwirlGirl
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mol = mass / Mr
so mol Fe = 28/56 = 0.5

therefore

mass = mol x Mr = 0.5 x 152 = 76grams

(This is what i'd do, it might be wrong in which case - sorry :o:)
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zahir27
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you are right btw
hahaha i knew what the answer was but i didn't know how to solve it tbh
its the techer who didnt explain how to do it properly :woo:
thanks x

(Original post by TwirlGirl)
mol = mass / Mr
so mol Fe = 28/56 = 0.5

therefore

mass = mol x Mr = 0.5 x 152 = 76grams

(This is what i'd do, it might be wrong in which case - sorry :o:)
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TwirlGirl
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(Original post by zahir27)
you are right btw
hahaha i knew what the answer was but i didn't know how to solve it tbh
its the techer who didnt explain how to do it properly :woo:
thanks x
phew :p: it wouldn't have boded well if i was wrong..got an A2 chemistry exam next week :p:
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zahir27
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haha well good luck then
I got mine tommorow :eek3: :eek3:
so doing some hardcore revision ahaha

(Original post by TwirlGirl)
phew :p: it wouldn't have boded well if i was wrong..got an A2 chemistry exam next week :p:
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MrMonopoly
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The method I use is to:

56/56 = 1

152/56 = 2.71428...

Then 2.71428... X 28 = 76g
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zahir27
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Now this is even more easier ahaha
thanks x :cool:

(Original post by MrMonopoly)
The method I use is to:

56/56 = 1

152/56 = 2.71428...

Then 2.71428... X 28 = 76g
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AquilaXenon
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(Original post by MrMonopoly)
The method I use is to:

56/56 = 1

152/56 = 2.71428...

Then 2.71428... X 28 = 76g
That's the method I always use. My teacher used to do it the other way during lessons it just gets so confusing. This makes it a lot easier, and the questions they give us in the exam should always be able to be done without using moles.
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User570431
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(Original post by TwirlGirl)
mol = mass / Mr
so mol Fe = 28/56 = 0.5

therefore

mass = mol x Mr = 0.5 x 152 = 76grams

(This is what i'd do, it might be wrong in which case - sorry :o:)
I can confirm this is correct. How was your exam?
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Bon1345
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I understand but where did you get 28 from??
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jrdoctorfudge
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the 28 is the mass of the compound, in this case it will be 28 grams and you need to do mass/relative atomic mass
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laurawatt
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(Original post by jrdoctorfudge)
the 28 is the mass of the compound, in this case it will be 28 grams and you need to do mass/relative atomic mass
Hiya! This thread was made in 2010 you can see the timestamp in the top right hand corner of each post
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