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# want some confirmation on this.... watch

1. Am i right in thinking to find the gradient of a curve, I differentiate it. And to find the gradient at a particular point of the curve, I sub in the 'x' value of the point into the differentiated equation???

and if the original equation is given by 'x=.....', I sub in the 'y' value of the point into the differentaited equation??
2. (Original post by W.H.T)
Am i right in thinking to find the gradient of a curve, I differentiate it. And to find the gradient at a particular point of the curve, I sub in the 'x' value of the point into the differentiated equation???

and if the original equation is given by 'x=.....', I sub in the 'y' value of the point into the differentaited equation??
I think first thing is true but, if you differentiate "x=..." with respect to y, thats not the gradient, as that would be dx/dy, as opposed to the gradient (dy/dx)
3. If it's "x = " then either make y the subject, or differentiate implicitly. Either way, you have to be subbing in x values.

Edit: when I say make y the subject, you'll have to differentiate after that of course.

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Updated: January 17, 2010
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