You are Here: Home >< Maths

# can anyone help with this calculus question? watch

1. differentiate log(sinh(x))
2. Does it not go to
1/coshx
?
3. Its chain rule

y = ln(sinh x)
u = sinh x
du/dx = cosh x

dy/dx = dy/du . du/dx

dy/dx = 1/u . cosh x
dy/dx = 1/sinh x . cosh x
dy/dx = coth x
4. Shows how much I need to to for FP2 in summer :P
.... I'm going to die xD
Sorry for the terrible inaccuracy.
5. thanks for the help

(Original post by billyb750)
Its chain rule

y = ln(sinh x)
u = sinh x
why is it y=ln(sinh x) rather than y=log(sinh x)?
6. I presumed, quite hard to differentiate log base 10....plus in real life you hardly use base 10. More usual to use base e or natural log...
7. (Original post by jag91uar)
thanks for the help

why is it y=ln(sinh x) rather than y=log(sinh x)?
It's just Log to the base e.

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: January 17, 2010
Today on TSR

### He lied about his age

Thought he was 19... really he's 14

### University open days

Wed, 25 Jul '18
2. University of Buckingham
Wed, 25 Jul '18
3. Bournemouth University
Wed, 1 Aug '18
Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams