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    differentiate log(sinh(x))
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    Does it not go to
    1/coshx
    ?
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    Its chain rule

    y = ln(sinh x)
    u = sinh x
    du/dx = cosh x

    dy/dx = dy/du . du/dx

    dy/dx = 1/u . cosh x
    dy/dx = 1/sinh x . cosh x
    dy/dx = coth x
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    Shows how much I need to to for FP2 in summer :P
    .... I'm going to die xD
    Sorry for the terrible inaccuracy.
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    thanks for the help

    (Original post by billyb750)
    Its chain rule

    y = ln(sinh x)
    u = sinh x
    why is it y=ln(sinh x) rather than y=log(sinh x)?
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    I presumed, quite hard to differentiate log base 10....plus in real life you hardly use base 10. More usual to use base e or natural log...
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    (Original post by jag91uar)
    thanks for the help



    why is it y=ln(sinh x) rather than y=log(sinh x)?
    It's just Log to the base e.
 
 
 
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