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    What translations have taken place when the graph y= 1/x is transformed to y= 2x+3/x-1 ???
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    You need to break up the fraction. So y= 2 + 5/(x-1)

    So vertical translation of +2.
    Horizontal of +1
    And Stretch of k=5
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    (Original post by JTeighty)
    You need to break up the fraction. So y= 2 + 5/(x-1)

    So vertical translation of +2.
    Horizontal of +1
    And Stretch of k=5
    ahh I SEE thank you xxx - how do you break up the fraction??
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    It comes up in FP2. Don't know why as its very easy.

    Very simply, make the term (x-1) appear in the numerator then let it cancel.
    So (2x+3)/(x-1) = (2(x-1)+3+2)?(x-1) = 2 + 5/(x-1)
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    (Original post by JTeighty)
    It comes up in FP2. Don't know why as its very easy.

    Very simply, make the term (x-1) appear in the numerator then let it cancel.
    So (2x+3)/(x-1) = (2(x-1)+3+2)?(x-1) = 2 + 5/(x-1)
    im still i a little confused..can you set it out again please
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    (Original post by klgyal)
    im still i a little confused..can you set it out again please
    If a term is both in the numerator and denominator they cancel. E.g. x/x =1/1=1

    In your example x-1 is the denominator. So you want to get a factor of x-1 on the numerator to cancel.

    So taking the numerator: 2x+3 = 2(x-1)+5 as 2(x-1)=2x-2 so add 5 to get 2x+3

    \frac{2(x-1)+5}{x-1} = \frac{2(x-1)}{x-1} + \frac{5}{x-1} = 2 +\frac{5}{x-1}
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    (Original post by JTeighty)
    If a term is both in the numerator and denominator they cancel. E.g. x/x =1/1=1

    In your example x-1 is the denominator. So you want to get a factor of x-1 on the numerator to cancel.

    So taking the numerator: 2x+3 = 2(x-1)+5 as 2(x-1)=2x-2 so add 5 to get 2x+3

    \frac{2(x-1)+5}{x-1} = \frac{2(x-1)}{x-1} + \frac{5}{x-1} = 2 +\frac{5}{x-1}
    thank - you xxx
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    (Original post by klgyal)
    thank - you xxx
    No problem but a bit of rep would
    be nice to have in return.
 
 
 
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