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# Graphs watch

1. What translations have taken place when the graph y= 1/x is transformed to y= 2x+3/x-1 ???
2. You need to break up the fraction. So y= 2 + 5/(x-1)

So vertical translation of +2.
Horizontal of +1
And Stretch of k=5
3. (Original post by JTeighty)
You need to break up the fraction. So y= 2 + 5/(x-1)

So vertical translation of +2.
Horizontal of +1
And Stretch of k=5
ahh I SEE thank you xxx - how do you break up the fraction??
4. It comes up in FP2. Don't know why as its very easy.

Very simply, make the term (x-1) appear in the numerator then let it cancel.
So (2x+3)/(x-1) = (2(x-1)+3+2)?(x-1) = 2 + 5/(x-1)
5. (Original post by JTeighty)
It comes up in FP2. Don't know why as its very easy.

Very simply, make the term (x-1) appear in the numerator then let it cancel.
So (2x+3)/(x-1) = (2(x-1)+3+2)?(x-1) = 2 + 5/(x-1)
im still i a little confused..can you set it out again please
6. (Original post by klgyal)
im still i a little confused..can you set it out again please
If a term is both in the numerator and denominator they cancel. E.g. x/x =1/1=1

In your example x-1 is the denominator. So you want to get a factor of x-1 on the numerator to cancel.

So taking the numerator: 2x+3 = 2(x-1)+5 as 2(x-1)=2x-2 so add 5 to get 2x+3

= + = 2 +
7. (Original post by JTeighty)
If a term is both in the numerator and denominator they cancel. E.g. x/x =1/1=1

In your example x-1 is the denominator. So you want to get a factor of x-1 on the numerator to cancel.

So taking the numerator: 2x+3 = 2(x-1)+5 as 2(x-1)=2x-2 so add 5 to get 2x+3

= + = 2 +
thank - you xxx
8. (Original post by klgyal)
thank - you xxx
No problem but a bit of rep would
be nice to have in return.

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