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    (Original post by Awesomesauce)
    Is this about the Unit 2 AQA Additional Science higher tier Physics 45 minute paper? Because, i havn't done mine yet. Wtf?
    no, Physic A Unit 2
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    (Original post by reshep)
    no, Physic A Unit 2
    Oh, thank ****.

    +1 rep for relief.
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    (Original post by ali242)
    the one marker?
    times the freq by 4
    draw 4 loops with 5 nodes
    shorten the string/tighten the string
    YES FLUKED IT! I was like, i have no idea what an overtone is, but i'm guessing it has something do with the frequency so i said "tighten the string" xD

    I think i got the second diagram and that last bit right out of that question, so all hope is not lost for me some marks for me. lol
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    Thank you everybody for highlighting all my careless silly mistakes and dashing my dreams of getting a 90+ mark :borat:

    No really, thank you :dry:
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    (Original post by Awesomesauce)
    Is this about the Unit 2 AQA Additional Science higher tier Physics 45 minute paper? Because, i havn't done mine yet. Wtf?
    No, AS level unit 2.
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    (Original post by Playboy King)
    Thank you everybody for highlighting all my careless silly mistakes and dashing my dreams of getting a 90+ mark :borat:

    No really, thank you :dry:
    It's how I feel too
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    (Original post by Playboy King)
    Thank you everybody for highlighting all my careless silly mistakes and dashing my dreams of getting a 90+ mark :borat:

    No really, thank you :dry:
    haha i feel the same way, stupid double spring so weight at X is twice what i put :/
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    I think I did aload of stupi stupid mistakes and I'm really Pissed that I have.
    I got the first 2 wrong which is 5 marks, and the electricity was 2 marker which I got wrong... and line of best fit, youngs modulus ect

    ergghh I hope the boundary's are really LOW.
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    (Original post by reshep)
    projectile motion was easseeeyyy, but that's because i nailed it in the night before

    it was 3920N per spring i think..

    14000 * 1.4 all divided by 2.5 = 7840 for both divide by 2 for each spring.

    I THINK i can't recall the exam
    Basically what i did for that question:

    As I recall it was 1.1 m away from rear tyres and 1.4m away from front? I think thats right. But i made the moments equal each other from either set of wheels.

    So I got 1.1 x Fr = 1.4 x Ff

    with Fr being force from the rear wheels and Ff being front.

    Then i divided both sides by 1.1 to get Fr = 1.27272727.. x Ff

    Since it must be true that Fr + Ff = 14000 N

    Then I figured Fr = 14000 / (1 + 1.272727...) = 6160 N

    Since there must have been 2.27272727.. lots of Fr within the force of 14000 N

    That seemed to be the logical way of going about it to me at least..

    then divide by 2 to get 3080 N
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    (Original post by Tomdc)
    Basically what i did for that question:

    As I recall it was 1.1 m away from rear tyres and 1.4m away from front? I think thats right. But i made the moments equal each other from either set of wheels.

    So I got 1.1 x Fr = 1.4 x Ff

    with Fr being force from the rear wheels and Ff being front.

    Then i divided both sides by 1.1 to get Fr = 1.27272727.. x Ff

    Since it must be true that Fr + Ff = 14000 N

    Then I figured Fr = 14000 / (1 + 1.272727...) = 6160 N

    Since there must have been 2.27272727.. lots of Fr within the force of 14000 N

    That seemed to be the logical way of going about it to me at least..

    then divide by 2 to get 3080 N
    wasn't it to take moments around A where A was the front wheels thus what you done was wrong?
    I apologise if you're are right btw :P
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    (Original post by ali242)
    the one marker?
    times the freq by 4
    draw 4 loops with 5 nodes
    shorten the string/tighten the string
    i just remembered i didnt draw the outer 2 as nodes, where the string starts.. u think that matters?
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    (Original post by reshep)
    wasn't it to take moments around A where A was the front wheels thus what you done was wrong?
    I apologise if you're are right btw :P
    I dont know anymore, i tried just used the moment around the whole thing as a base equation to start off.. I'll ask my physics teacher tommorow hahah i dont mind if im wrong cos I should have enough for an A still, i aint studied this in a classroom for ages now since im doing it as a retake, and my brain has prehaps been frazzled by A2 maths and physics techniques
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    (Original post by Tomdc)
    I dont know anymore, i tried just used the moment around the whole thing as a base equation to start off.. I'll ask my physics teacher tommorow hahah i dont mind if im wrong cos I should have enough for an A still, i aint studied this in a classroom for ages now since im doing it as a retake, and my brain has prehaps been frazzled by A2 maths and physics techniques
    Let me know the outcome please i don't see my physics teacher until thursday
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    I have probably done worse than last year.

    I dont think I'll get 94/120!
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    (Original post by Tomdc)
    i just remembered i didnt draw the outer 2 as nodes, where the string starts.. u think that matters?
    Yes it said mark all nodes. You missed 2 therefore you lose the mark.
    Another question that was sposed to throw you off. This paper was full of em :/
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    (Original post by Playboy King)
    Thank you everybody for highlighting all my careless silly mistakes and dashing my dreams of getting a 90+ mark :borat:

    No really, thank you :dry:

    Hey, you're more than welcome

    I think I've messed it up. Everyone in my class struggled. I'll be lucky to scrape a C. I got more blank answers than anything else. And that's with 5 weeks non-stop revision, let alone two days :eek:
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    (Original post by Tomdc)
    Basically what i did for that question:

    As I recall it was 1.1 m away from rear tyres and 1.4m away from front? I think thats right. But i made the moments equal each other from either set of wheels.

    So I got 1.1 x Fr = 1.4 x Ff

    with Fr being force from the rear wheels and Ff being front.

    Then i divided both sides by 1.1 to get Fr = 1.27272727.. x Ff

    Since it must be true that Fr + Ff = 14000 N

    Then I figured Fr = 14000 / (1 + 1.272727...) = 6160 N

    Since there must have been 2.27272727.. lots of Fr within the force of 14000 N

    That seemed to be the logical way of going about it to me at least..

    then divide by 2 to get 3080 N
    Yes that the answer i got i think. BTW all the other posts.... it didnt ask about all the tyres.... only the rear tyres so u had to divide by 2.:yep:
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    If it's any consolation guys, the AS module was a piece of cake

    Don't badmouth physics, you may put me off doing it next year!
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    (Original post by Tomdc)
    I dont know anymore, i tried just used the moment around the whole thing as a base equation to start off.. I'll ask my physics teacher tommorow hahah i dont mind if im wrong cos I should have enough for an A still, i aint studied this in a classroom for ages now since im doing it as a retake, and my brain has prehaps been frazzled by A2 maths and physics techniques
    you had to work it out like taking to support forces into account. because the lorry was supported at the rear and the front.
    moment from b = distance of the a from the center of mass times by the force then divided by the distance acroos a to be

    so i done
    14000 x 0.9 divided by 2.3 = something then divided by 2

    so i got 2750.
    but i may be wrong
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    (Original post by kishan55)
    you had to work it out like taking to support forces into account. because the lorry was supported at the rear and the front.
    moment from b = distance of the a from the center of mass times by the force then divided by the distance acroos a to be

    so i done
    14000 x 0.9 divided by 2.3 = something then divided by 2

    so i got 2750.
    but i may be wrong
    you sure?

    i thought if your taking moments around a point all forces directly on that point are ignored?
 
 
 
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