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ahhh guys! please help!!! really hard maths C3 differentiation Watch

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    x = 1 + (lny)/(ln5)

    find dx/dy

    i have got as far as saying using the quotient rule, lny = u, ln5 = v

    so ln5(1/y) - nothing as ln5 = 0, times lny = 0.. or do you just write lny?
    divided by ln5^2

    so in summary, i have got ln5(1/y)/(ln5)^2

    is this right?? I am confused plz help guys!!

    + rep thanks!
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    (Original post by desertwarrior)
    x = 1 + (lny)/(ln5)

    find dx/dy

    i have got as far as saying using the quotient rule, lny = u, ln5 = v

    so ln5(1/y) - nothing as ln5 = 0, times lny = 0.. or do you just write lny?
    divided by ln5^2

    so in summary, i have got ln5(1/y)/(ln5)^2

    is this right?? I am confused plz help guys!!

    + rep thanks!

    in5 is a constant.

    The differential of Iny is 1/y
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    (Original post by steve2005)
    in5 is a constant.

    The differential of Iny is 1/y
    ah k, so when differentiating the u (dv/dx)
    it is just 0 times lny which is 0?
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    ^ What he said. ln5 can be taken as a constant and can be written as

    1/ln5 *lny.
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    ahhh i get it now thansk guys!!!!!
 
 
 
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