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    f(x) = x^2 +6x, x> -3

    ok so I've completed the square.
    sqrt(x+9) -3

    found the range x > 3

    how do i find the domain?

    edit: of the inverse
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    well the domain of a quadratic function is just all the real numbers
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    Its given to you
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    no

    the domain and the range of the inverse.
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    (Original post by SeekerOfKnowledge)
    f(x) = x^2 +6x, x> -3
    I believe the domain is x>-3, although if that wasn't there then it would be all real numbers.
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    (Original post by SeekerOfKnowledge)
    no

    the domain and the range of the inverse.
    oh.

    well the domain of the inverse is the range of the original function
    and the range of the inverse is the domain of the original function
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    (Original post by starofale)
    oh.

    well the domain of the inverse is the range of the original function
    and the range of the inverse is the domain of the original function
    oh yeah, thanks
 
 
 
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