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# grrrr forgot implicit differentiation - rep for first who tells watch

1. hi, i am annoyed that I have forgotten how to differentiate easy stuff, like e^((x^2)y)

just show me d/dx of it, and show me a bit how you did it

(rep for first who shows me, and is right ofc :P)
2. (2xy+x^2.dy/dx)e^((x^2)y)

I think because e^whatever is the same and then you multpily by the differential of the power where u have to use the product rule
3. (Original post by Jukukiwaiyi)
hi, i am annoyed that I have forgotten how to differentiate easy stuff, like e^((x^2)y)

just show me d/dx of it, and show me a bit how you did it

(rep for first who shows me, and is right ofc :P)
Use the chain rule. Let u=x^2y. Then y=e^u. By the chain rule,
dy/dx = dy/du x du/dx = e^u x du/dx. For du/dx, use the product rule, eg, du/dx = 2xy + x^2 dy/dx. Then just substitute this back in, so dy/dx = [2xy+x^2 dy/dx]e^(x^2y), then just collect like the dy/dx etc

4. Hope that helps, just use product rule.
5. thanks for help guys

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