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    i know that for the right side of it you make x^2 the constant and then differentiate y, which derives x^2, but for the left side... I get (d(x^2)/dy)*y... is that right? because it just seems a bit.... abnormal, I haven't come across something like that before
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    think of the equation as (y^2)x with respect to x if its easier and then use product rule with implicit differentiation.
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    (Original post by hay.hay)
    think of the equation as (y^2)x with respect to x if its easier and then use product rule with implicit differentiation.
    you think it's right though?:P
    the answer i gave
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    Answer is

     \frac{d}{dx}[x^2y] = x^2\frac{dy}{dx} + 2xy

    Use product rule to get the two terms.

    First hold x constant and implicitly differentiate y to get  x^2\frac{dy}{dx}

    Then hold y constant and differentiate x to get

     2xy

    Then sum together for full answer!
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    When you differentiate y with respect to x, you get dy/dx.

    So when you differentiate x with respect to y, you get dx/dy.

    Differentiate implicitly, but don't get confused and write down dy/dx when you differentiate y.

    The answer is:
    Spoiler:
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    x^2 + 2xy(dx/dy)


    I know we're not supposed to post full solutions but the OP is wrong, and so is the poster who obviously misread the question and has differentiated the function with respect to x.
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    (Original post by spread_logic_not_hate)
    Answer is

     \frac{d}{dx}
    This, and onwards, is wrong. Read the question again. :p:
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    This, and onwards, is wrong. Read the question again.
    Lol so it is, ah the force of years of habit coming into play... At least the method is right!
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    (Original post by Jukukiwaiyi)
    you think it's right though?:P
    the answer i gave
    I have no idea what your question even means! lol my boyfriend must have posted on my account thinking it was his! I'll ask him
 
 
 
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