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# c3 differentiation question part 2 watch

1. given that y = e^3x -2x

find any stationary points of the curve and determine their nature.

ok so i tried to do it

dy/dx = 2e^2x - e^x

and when dy/dx = 0

2e^2x - e^x = 0

i tired to solve it but i couldnt, any ideas?
2. eh?

right?

If so, your dy/dx is wrong.
3. (Original post by SeekerOfKnowledge)
dy/dx = 2e^2x - e^x
This line is completely wrong. Check that you haven't mixed it up with another question.
4. if y=e^3x -2x
then dy/d = 3e^3x -2

at stationary pint
3e^3x -2=0
3e^3x=2
e^3x=2/3
x=ln(2/3) /3
then sub that x value in oringinal for y
5. sorry i have mixed the question

the equation is:

y= e^2x + e^-x
6. 2e^2x - e^-x = 0

2e^2x - 1/e^x = 0

let e^x = y

(2y^2 -1/y = 0 ) *y

.
.
.
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7. 2e^2x = e^-x

Solve.

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