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# OCR MEI FP1 20th January 2010 pm watch

1. You're both right, I made a mistake, thanks for pointing it out corrected in post.
2. DAMMIT - I now realise that I got that locus question wrong (the one with 43 + 47j or whatever), since I only did arg of that and not arg (43 + 47j - (2 + j)).

There'a another 2 marks Feck...
3. Ive realised now that not only did I forget to finish off the induction question with the little statement at the end, I also completely forgot to do the inequalities at the end of the graph question. Hopefully will still have an A though. But stupid silly mistakes none the less
4. (Original post by Donor)
Ive realised now that not only did I forget to finish off the induction question with the little statement at the end, I also completely forgot to do the inequalities at the end of the graph question. Hopefully will still have an A though. But stupid silly mistakes none the less
-2 for forgetting statement on induction, -3 for forgetting inequalities probably, so almost certainly still 10+ marks into an A.
5. (Original post by matt2k8)
-2 for forgetting statement on induction, -3 for forgetting inequalities probably, so almost certainly still 10+ marks into an A.

I think even -5 marks for that is a bit harsh. Why would you lose 3 marks for forgetting to omit the asymptote in the inequality?
6. (Original post by OL1V3R)
DAMMIT - I now realise that I got that locus question wrong (the one with 43 + 47j or whatever), since I only did arg of that and not arg (43 + 47j - (2 + j)).

There'a another 2 marks Feck...

I think you will only lose a mark for this, (I hope so anyway!)
7. (Original post by Tallon)
I think even -5 marks for that is a bit harsh. Why would you lose 3 marks for forgetting to omit the asymptote in the inequality?
I interpeted the post as him missing out the inequalities bit of the question altogether
8. how do you find out the answer to a question like |z - 1| = |z|
i know pretty much everything about modulus and argument but im not sure how to answer it when theres two z's i know its a straight line but no other details if anyone can help me
9. (Original post by godexists1234)
how do you find out the answer to a question like |z - 1| = |z|
i know pretty much everything about modulus and argument but im not sure how to answer it when theres two z's i know its a straight line but no other details if anyone can help me
Well, |z-1| is the distance of z from the point 1 + 0j, and |z| is the distance of z from the point 0 + 0j, so it's just points of equal distance from (0,0) and (1,0) (i.e the perpendicular bisector of the line between these 2 points)

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