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OCR (MEI) Mathematics C3 20/01/2010 watch

  • View Poll Results: How did you find the paper?
    Easy
    13
    19.12%
    OK-ish
    28
    41.18%
    Hard
    25
    36.76%
    I'm not sure/ i didnt take the exam/ ?
    2
    2.94%

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    (Original post by lilmewho)
    What did you guys get for P and Q.
    P( pie/6, 0)
    Q( pie/2, 0)
    anyone agree?
    yeah i got the same for P. couldnt work out the co-ord of Q, but luckily p was the important one
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    14
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    OMG that was awful

    Left quite a few questions. For some reason I couldn't even do the first Q!!
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    (Original post by ily_em)
    OMG that was awful

    Left quite a few questions. For some reason I couldn't even do the first Q!!
    SAMEEE! you would think that its the first question so it would be easyy... but now! they give us the hardest one they possibly can!.
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    In Q1 was x = ln5?
    • Thread Starter
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    horrible paper, was powning the rest.
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    I also got a negative gradient. Did anyone else??
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    That's what I had. Divide both sides by the e's, then ln both sides.
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    (Original post by MarkS2)
    In Q1 was x = ln5?
    yeah thats what i got, u had to make them equal and thats the correct answer
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    I got a negative gradient in the trig question at -pi/2 at P (x = pi/6)
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    (Original post by MarkS2)
    In Q1 was x = ln5?
    Yea, you were asked to solve e^2x - 5e^x = 0
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    cant belive i wrote
    arccos(pi/6) and arccos (pi/2)
    daamn
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    Does it matter that i used 30 instead of pi/6 ? I did the whole question in degrees as I wasn't sure, and there was no indication either way (to my knowledge and I looked)
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    Always seems to happen to me; the past papers that I do are really pretty easy but then the real ones are disgustingly hard. (except c2
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    In integration/differentiation the angle(s) are always supposed to be in radians I believe, so I think it does.
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    yeah, I'm resitting it...I don't even want to know my grade :|
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    (Original post by Schismist)
    Does it matter that i used 30 instead of pi/6 ? I did the whole question in degrees as I wasn't sure, and there was no indication either way (to my knowledge and I looked)
    yeah i think it has to be radians, but you will still get some marks as it isnt wrong, just incorrect notation
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    right. for q5 the transformation one did you explicity have to specify what a b and c were. cuz i did the question right but i just wrote it in terms of sin x - but i suppose that does show what a b and c are ?
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    From what I can remember:

    1) x = ln5

    5) Graphs one I think. for i) I got b=3, a=0, c=2 ii) a=1 b=-1 c=1 or b=1 c=-1

    6) gf(x) = g[f(x)] Substitute functions -f(x) and f(-x) into composite function, should get answer as g[f(x)] both times (under the condition that g(x) is even), therefore composite function is even.

    7) Trig identity proof I think

    9)iii) f''(x)=0 find value of x, sub into f'(x) and that should give you max gradient.

    Not 100% sure that's right, correct me if I'm wrong.

    On the whole, I thought the paper wasn't too bad.
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    Did anyone get (pi/18) - (1/9) for one of the integration answers (can't remember which one) think it was \int\limits_{0}^{\frac{\pi }{6}}{x\cos 3xdx=\frac{\pi }{18}-\frac{1}{9}}
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    (Original post by MarkS2)
    Did anyone get (pi/18) - (1/9) for one of the integration answers (can't remember which one)
    YEH
 
 
 

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