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    (Original post by hellopoppet)
    I think so!
    No I mean I agree with you! I summed from 1 to inf not from 2 to inf by mistake.
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    The argand diagram, should it be a bisector or 2 circles?
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    2 circles I think (hope!!).
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    A pair of congruent circles.
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    to mr.m the answer for question 10(iv) i wrote from (1,1) to (21,1). Is that equeallyacceptable
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    (Original post by Mr M)
    A pair of congruent circles.
    Wonderful, it's just that 2 people in my class got a bisector and another and I got two circles, so we were debating. Thank you so much.
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    (Original post by imzi)
    to mr.m the answer for question 10(iv) i wrote from (1,1) to (21,1). Is that equeallyacceptable
    yes
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    can anyone remember the question for 2ii?
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    (Original post by TWP1992)
    can anyone remember the question for 2ii?
    find the value of

    (alpha + 1) (beta + 1) (gamma + 1)
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    i expanded that and got -D/A + C/A + 1 and used the values from u expression and got 9.5 not 4
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    No need to expand, x=u-1, so u=x+1.
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    (Original post by mcp2)
    No need to expand, x=u-1, so u=x+1.
    thanks, i wasn't sure whether alpha and beta and gamma referred to the original or the expression you worked out
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    Q6, I somehow managed to get 3.2 for part a). Then on b), this obviously meant my values for p and q were wrong. How many marks (3 for first, 4 for second) do you think i'll get/drop?
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    what was the question for 9ii?
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    (Original post by TWP1992)
    what was the question for 9ii?
    solve

    2x - y + z = 1
    3y + z = 2
    x + y + az = 2
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    Solve the simultaneous equations, can't remember the matrix though :/
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    (Original post by destined-monkey)
    Q6, I somehow managed to get 3.2 for part a). Then on b), this obviously meant my values for p and q were wrong. How many marks (3 for first, 4 for second) do you think i'll get/drop?
    I may regret asking this but where did you get 3.2 from?

    You will clearly lose 3 accuracy marks (1 in the first part and 2 in the second part). It is possible you could all get the method marks but it depends what you did.
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    i was just wondering whether there was a reason you didn't find the value of a?
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    (Original post by TWP1992)
    i was just wondering whether there was a reason you didn't find the value of a?
    Because the question didn't ask you to find a.

    And because we only have three equations and four unknowns.
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    but you can find a quite easily, did it ask you to solve in terms of a?
 
 
 
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