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Official Edexcel C3 Discussion Thread

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can someone please help me. i'm looking for a song that has 'lalala' repeated in it and has lots of clapping. its quite catchy and sounds similar to something that the ting tings would release.
Reply 21
Avatar for Orwell
Orwell
3
unknownking321
can someone please help me. i'm looking for a song that has 'lalala' repeated in it and has lots of clapping. its quite catchy and sounds similar to something that the ting tings would release.


Possibly Gobbledigook by Sigur Ros

http://www.youtube.com/watch?v=zfKw5r7M7MQ
:no: but thanks for trying. anyone else?
unknownking321
can someone please help me. i'm looking for a song that has 'lalala' repeated in it and has lots of clapping. its quite catchy and sounds similar to something that the ting tings would release.

That sounds a lot like Lady Gaga's 'Bad Romance'??
bittersweet.poetry
That sounds a lot like Lady Gaga's 'Bad Romance'??


:no: i'd have recognised that song

the song i'm looking for may have actually been something like 'nanana' and the clapping sounds like the first few seconds of this song

http://www.youtube.com/watch?v=hlYMoSubtHc
Im really good at the whole of this module (for once), except trig!!! Its so annoying
doing solomon papers is demotivating
Reply 27
Avatar for Doughboy
Doughboy
OP
9
Pheylan
sin(x + 2x) - sinx = 0
sinxcos2x + sin2xcosx - sinx = 0
sinx(1 - 2sin^2(x)) + 2sinxcos^2(x) - sinx = 0
sinx - 2sin^3(x) + 2sinxcos^2(x) - sinx = 0
sinx - 2sin^3(x) + 2sinx(1 - sin^2(x)) - sinx = 0
sinx - 2sin^3(x) + 2sinx - 2sin^3(x) - sinx = 0
2sinx - 4sin^3(x) = 0
sinx - 2sin^3(x) = 0
sinx(1 - 2sin^2(x)) = 0


I'm ashamed to ask... but can you please solve this? I was never good at C2 ;_; I still don't know C2 trig that well nor do I know circles.

And, I just remembered. Is it possible for them to ever bring back circles in C3?
Reply 28
Avatar for hobo06
hobo06
16
I watched Lesbian Vampire Killers last night, and there was a song near the beginning, when you first see the girls, coming out of the bar. All I can remember is the word 'Woman' (I'm guessing the name of the song), as I was quite tired. It's bugging me as to what it is as I've heard it before. Any one know?
Doughboy
I'm ashamed to ask... but can you please solve this? I was never good at C2 ;_; I still don't know C2 trig that well nor do I know circles.

And, I just remembered. Is it possible for them to ever bring back circles in C3?

isnt is just sinx=0 or sinx=+/- (root)1/2?
where does circles come from? xx
Reply 30
Avatar for Pheylan
Pheylan
Doughboy
I'm ashamed to ask... but can you please solve this?


sure :smile:

sinx(1 - 2sin^2(x)) = 0

sinx = 0

1 - 2sin^2(x) = 0
2sin^2(x) = 1
sin^2(x) = 1/2
sinx = +/- sqrt(1/2)
x = arcsin(+/- sqrt(1/2))

so x = 0 degrees
x = 45 degrees
x = -45 degrees

although it was 0 < x < 360, so

x = 0
x = 45
x = 135
Reply 31
Avatar for Milan.
Milan.
3
I have s1 s2 and c3 this month!
out of the 3, i've done soooo much C3, but not enough of the other two


I haven't read the thread but in addition to the OP the edexcel past papers
there is:

edexcel mock paper, edexcel specimen, c3 paper at the back of the c3 book
5 edexcel practise papers
12 solomon papers
12 elmwood papers (not reccomended, all are significantly harder than usual)

stuck for more papers... anyone?
Reply 32
Avatar for Doughboy
Doughboy
OP
9
indie_couture
isnt is just sinx=0 or sinx=+/- (root)1/2?
where does circles come from? xx


Oh, circles come in no where! That was just me whining :rolleyes:
Reply 33
Avatar for Doughboy
Doughboy
OP
9
Pheylan
sure :smile:

sinx(1 - 2sin^2(x)) = 0

sinx = 0

1 - 2sin^2(x) = 0
2sin^2(x) = 1
sin^2(x) = 1/2
sinx = +/- sqrt(1/2)
x = arcsin(+/- sqrt(1/2))

so x = 0 degrees
x = 45 degrees
x = -45 degrees

although it was 0 < x < 360, so

x = 0
x = 45
x = 135


O_O

Isn't it:

sinx=0sinx=0
x=0,x=180,x=360x=0, x=180, x=360

sinx=±1/2sinx=\pm \sqrt{1/2}
x=−45,x=45,x=135,x=225x=-45, x=45, x=135, x=225

:eek3:

Seems correct, init?
Reply 34
Avatar for Pheylan
Pheylan
Doughboy
O_O

Isn't it:

sinx=0sinx=0
x=0,x=180,x=360x=0, x=180, x=360

sinx=±1/2sinx=\pm \sqrt{1/2}
x=−45,x=45,x=135,x=225x=-45, x=45, x=135, x=225

:eek3:

Seems correct, init?

ah yeah i forgot about 180 and 360, but -45 is out of the range and 225 is wrong
Reply 35
Avatar for Doughboy
Doughboy
OP
9
Pheylan
ah yeah i forgot about 180 and 360, but -45 is out of the range and 225 is wrong


Ok yes -45 is wrong.

But 225 is right.

sin(225*3) - sin225 = 0

Just add -45 to 270 (to get negative sin in 4th quadrat).
Just youtubed it and it is! thankyou so much, it was drivingme crazy
such an amazing song
can anyone help with graphs, domains, range etc?

When it says draw the graph y=a-x or 2x-2a

It should be easy but I am rubbish at graphs! xx
Im usually really good at C3 but could somebody help with this question, as I just can't get the right answer.

Simplify:
Reply 39
Avatar for Doughboy
Doughboy
OP
9
OrangeStu
Im usually really good at C3 but could somebody help with this question, as I just can't get the right answer.

Simplify:


−x+x2(x−2)−20x2+x−6-x + \dfrac{x^2}{(x-2)} - \dfrac{20}{x^2+x-6}

−x+x2x−2−20(x−2)(x+3)-x + \dfrac{x^2}{x-2} - \dfrac{20}{(x-2)(x+3)}

−x(x2+x−6)+x2(x+3)−20(x−2)(x+3)\dfrac{-x(x^2+x-6)+x^2(x+3)-20}{(x-2)(x+3)}

−x3−x2+6x+x3+3x2−20(x−2)(x+3)\dfrac{-x^3-x^2+6x+x^3+3x^2-20}{(x-2)(x+3)}

2x2+6x−20(x−2)(x+3)\dfrac{2x^2+6x-20}{(x-2)(x+3)}

(2x+10)(x−2)(x−2)(x+3)\dfrac{(2x+10)(x-2)}{(x-2)(x+3)}

2x+10x+3\dfrac{2x+10}{x+3}

:cool: I verified my answer using different values of x. Seems I am correct :redface:

I've noticed that factorising quadratic expressions is key here.

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