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    (Original post by bab)
    i got 4/(9x+3)(x-1) for that first questions.Is that correct?
    Yes, I posted the model solutions on here a few pages back.
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    just wondering, what was required to get 90% last year, i know 67/75 was for an A, was it 71 by any chance?
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    (Original post by sulexk)
    just wondering, what was required to get 90% last year, i know 67/75 was for an A, was it 71 by any chance?
    yes it was.
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    I thought it was Ok, found it a little harder then the most recent papers, I think/hope the grade boundaries may be quite low.
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    really 71 to get 90%

    I see
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    (Original post by Arsey)
    agreed; however, it is worth remembering it doesn't matter how difficult any of us thought it was, it doesn't matter how it compares to papers in previous years. All that matters is how students have done on the paper this time. Some on here seem pretty confident they have done well. We'll see.

    Not worth worrying about, nothing can be done about it now.
    Appreciate the markscheme, however, for the last question:

    so for g(x) = 1 ln(x-1) = 1 therefore, x -1 = e, therefore x = (1 +e)>1

    Therefore fg(e+1) = f(1)

    therefore fg(x)>=3 . The fact that x>1 for g(x) is irrelevent, as g(x) is the input. to f(x)
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    any ideas on how many marks the cot2x=0, solution will be worth?
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    riiiiight, so i think i got

    66 PLUS however many they'll give for the two obvious solutions in q8

    :awesome:
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    (Original post by sulexk)
    any ideas on how many marks the cot2x=0, solution will be worth?
    2/3 marks.

    They need to give at least 3 for the 'up to factorisation' process. Then 2 each for the solutions.
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    To get an A* you need 90% on c3 and c4 right?
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    (Original post by sulexk)
    any ideas on how many marks the cot2x=0, solution will be worth?
    2 marks
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    I'm going to go with Arsey and say 55 for 80 UMS too, there was more than 1 area to lose marks easily on for this paper.. probably a rebound considering people who did C3 in June '09 were having a laugh..

    I'd say I got anywhere between 45-57 tbh depending on method marks too..
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    (Original post by ollie_91)
    To get an A* you need 90% on c3 and c4 right?
    the sum of your C3 and C4 mark has to be 180 or more
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    as long as the total is 90% i think.

    so as long as you obtain 180/200 you get A* in A2 math. I assume that is how it works..

    thanks!
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    (Original post by xSkyFire)
    55 for 80 UMS
    :coma:

    could someone explain how UMS works? like, once they find how many marks = 80 UMS etc, what do they do for stuff like 85 UMS?
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    Will I lose marks if I get the right answer but use a different method?

    For the x = tan y question:

    \frac {dx}{dy} = \sec^2 y = \frac {1}{\cos^2 y}

    \frac {dy}{dx} = \cos^2 y

    Then I drew a triangle, put the adjacent side as 1 and the opposite as x, therefore the hypotenuse is \sqrt {1 + x^2}. So, since cos y = A/H,

    \cos^2 y = \frac {1}{1 + x^2}


    For 9b) I did:

    

3^{x} = e^{xln3}

    3^{x} e^{7x+2} = e^{xln3} e^{7x+2}

     = e^{xln3 + 7x + 2} = 15

    x ln 3 + 7x + 2 = ln 15

    x (ln 3 + 7) = ln 15 - 2

    x = \frac {ln 15 - 2}{ln 3 + 7}



    Anybody know if I'll lose marks for that?
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    I did something really stupid and forgot to label the axis for the graphs.
    I got the write shape and co-ordinates, and in previous mark schemes this is what the marks are given for, but am I likely to lose marks because of forgetting to label the axis?
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    3a) Express 5cosx - 3sinx in the form Rcos(x + a), where R > 1/2 and 0 < a < pi/2.



    i worked out R and a correctly but i didn't "express" it in that form - that is, i didn't explicitly say "5cosx - 3sinx = (root34)sin(x + 0.54)", will i lose a mark?
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    (Original post by Noble.)
    Damn, the only question I got wrong was the first question when simplifying the fraction. I just left it as (4x+4)/(3x^2-3)(3x+1). How many marks will I lose, one or two?
    ahah i left it like that too my teacher said it is 3 marks.
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    (Original post by john1234567)
    3a) Express 5cosx - 3sinx in the form Rcos(x + a), where R > 1/2 and 0 < a < pi/2.



    i worked out R and a correctly but i didn't "express" it in that form - that is, i didn't explicitly say "5cosx - 3sinx = (root34)sin(x + 0.54)", will i lose a mark?
    Well looking at previous mark schemes I don't think you'll lose a mark for not writing it in that form.
 
 
 
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