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    If anyone here wants a moderate challenge, try out the C3 January 2007 paper, question 8 iia) and ii b) was only attempted by 10% of the candidates according to the Exam Report..
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    (Original post by htn)
    If anyone here wants a moderate challenge, try out the C3 January 2007 paper, question 8 iia) and ii b) was only attempted by 10% of the candidates according to the Exam Report..
    Been posted a few pages back :p:
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    (Original post by htn)
    If anyone here wants a moderate challenge, try out the C3 January 2007 paper, question 8 iia) and ii b) was only attempted by 10% of the candidates according to the Exam Report..
    Lol. I hated that question!

    Some useful (?) files for C3 (from ExamCafe):

    Hot Tips

    Glossary

    Exam Language

    Common Mistakes
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    Help?
    http://www.thestudentroom.co.uk/show....php?t=1154529
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    have there actually been any remainder theorem questions? (because I don't remember any!)
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    hi,
    does any one have the jan 09 and june 09 past question papers?
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    how would i solve x|2x+a|-1=0
    I treated the modulus as a bracket and times 2x+a by x and got a quadratic....is this the right thing to do?
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    (Original post by MIKE ESSIEN IS QUITE SICK)
    how would i solve x|2x+a|-1=0
    I treated the modulus as a bracket and times 2x+a by x and got a quadratic....is this the right thing to do?
    That's not the way to solve equations with the modulus function! What are you solving here, x in terms of a? Add one to both sides and divide through by x (|2x+a|=1/x). Then do a quick sketch of the graphs |2x+a| and 1/x and consider points of intersection.
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    (Original post by LysiaK)
    The trig identity for cos(A) - cos(B) is in the formula booklet: -2sin(\frac{A+B}{2})sin(\frac{A-B}{2}).


    If you meant you wanted the proof:

    Use the identities
    cos(A + B) = cos(A)cos(B) - sin(A)sin(B)
    and
    cos(A - B) = cos(A)cos(B) + sin(A)sin(B)

    Subtract one from the other
    cos(A + B) - cos(A - B) = -2sin(A)sin(B)

    Let A + B = P and A - B = Q
    so, A = \frac{P + Q}{2} and B = \frac{P - Q}{2}

    Therefore, cos(P) + cos(Q) = -2sin(\frac{P + Q}{2})sin(\frac{P - Q}{2})

    And in your case, you'd just sub in the 5x and x as P and Q
    note: this type of question has been removed from the syllabus.
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    (Original post by ScaryKid_ScaringKids)
    Sorry i cant help you...im looking for a song tooo
    the vid is this guy playing the piano in a room filled with moving toys
    Owl City - Fireflies
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    (Original post by milliondollarcorpse)
    That's not the way to solve equations with the modulus function! What are you solving here, x in terms of a? Add one to both sides and divide through by x (|2x+a|=1/x). Then do a quick sketch of the graphs |2x+a| and 1/x and consider points of intersection.
    ok thanks Also if you have to sketch the function y= 3|x-1|-2 is this a y=f(|x|) . I sketched the graph correctly by doing the modules of x-1 in the x axis and then doing the scale factor 3 vertical stretch and translation 2 units down. Is this the wrong way to do it?
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    (Original post by MIKE ESSIEN IS QUITE SICK)
    ok thanks Also if you have to sketch the function y= 3|x-1|-2 is this a y=f(|x|) . I sketched the graph correctly by doing the modules of x-1 in the x axis and then doing the scale factor 3 vertical stretch and translation 2 units down. Is this the wrong way to do it?
    Yup that's right
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    (Original post by milliondollarcorpse)
    Yup that's right
    isiit...my teacher was saying that y= 3|x-1|-2 would be a modulus in the y axis........are you doing s2 on tuesday ?
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    (Original post by Pheylan)
    note: this type of question has been removed from the syllabus.
    i have seen many papers with them
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    (Original post by PurpleMonkeyDishwasher)
    CSS - Alala? Not sure if there's clapping in that though. I'll give it some thought and probably get back to you...

    I think it's Santogold.
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    Can anyone help me? This song is sort of dance/electro/house, and it has a guy speaking in a really posh voice, and he says 'is this what all the trendy kids are listening to these days?' He also alludes parts of the song being electro or house or breakbeat. It ends with 'Remember, always stick to your guns' and 'peace out *************.'
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    (Original post by milliondollarcorpse)
    Rearrange x =4sin (2y + 6) in terms of y and substitute it into dy/dx

    Let x^2=y

    Solve y^2-8y-12=0
    thankyou!
    I was wondering if you could help with domains/range.
    How do you know if it is all real numbers XER or whatever.
    for the range do you put in the x values of the domain or x=0?
    i can only sometimes get these right xxx
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    Can anybody help me as to who sings this song or what the song is called. It's in the background of this video:

    http://www.youtube.com/watch?v=svrOx...eature=related

    Thanks to anyone that can help
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    (Original post by kosy91)
    i have seen many papers with them
    Really?!

    O_O
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    Hahaa i tried using shazam on my phone but it didnt work! :p:
 
 
 
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