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    Firstly, Find the x coordinates of intersection of the curves y = (x+3) (x-2) (x-1) & y = 3/2 (x+2) (2-x)?

    And then Hence find the area between the two curves where x > 0


    Thanks for any help!
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    C3 is over, thanks for playing the game! Better luck next time
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    (Original post by Genesis-ar92)
    C3 is over, thanks for playing the game! Better luck next time
    Some people have it in June. :facepalm2:
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    He might just be really, really eager? :lolwut:

    Edit; and if you really want to know, make = to 0
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    (Original post by Genesis-ar92)
    C3 is over, thanks for playing the game! Better luck next time
    I am in my first year, I have it in june, so you feel stupid?
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    (Original post by TwirlGirl)
    He might just be really, really eager? :lolwut:

    Edit; and if you really want to know, make = to 0
    Nope I do double, and thanks? Still not too sure
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    (Original post by EzPz)
    Firstly, Find the x coordinates of intersection of the curves y = (x+3) (x-2) (x-1) & y = 3/2 (x+2) (2-x)?

    And then Hence find the area between the two curves where x > 0


    Thanks for any help!
    Since y = (x+3) (x-2) (x-1) & y = 3/2 (x+2) (2-x), you've got (x+3) (x-2) (x-1) = 3/2 (x+2) (2-x).
    They equal one another because you want to find where they intersect. :yep:

    So then you can rearrange and solve for x...?

    EDIT: For the area between the two curves, you'd use integration - remember the area is the integral of 'the top curve minus the bottom curve'. To determine which curve is the 'top' one and which the 'bottom' one, consider the turning points of each function (easy to read off, because both curves' equations are fully factorised for you).
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    (Original post by EzPz)
    Nope I do double, and thanks? Still not too sure
    Oops :o: read the question wrong!! Sorry!
    Make the 2 equations equal to eachother and solve to find x
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    (Original post by EzPz)
    I am in my first year, I have it in june, so you feel stupid?
    errr no why are you revising for an exam in June now?? I don`t feel stupid at all haha
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    (Original post by EzPz)
    Firstly, Find the x coordinates of intersection of the curves y = (x+3) (x-2) (x-1) & y = 3/2 (x+2) (2-x)?

    And then Hence find the area between the two curves where x > 0


    Thanks for any help!
    and also this is not C3
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    (Original post by Genesis-ar92)
    errr no why are you revising for an exam in June now?? I don`t feel stupid at all haha
    Why am I revising? No... It's called homework, learn to use an apostrophe.
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    (Original post by EzPz)
    Why am I revising? No... It's called homework, learn to use an apostrophe.
    ok please shut up and stop being pedantic... You don`t deserve and apostrophe!
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    (Original post by Genesis-ar92)
    errr no why are you revising for an exam in June now?? I don`t feel stupid at all haha
    what, so you can't do questions for an exam if it's five months away?

    and what makes you think it's not C3?
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    (Original post by Genesis-ar92)
    errr no why are you revising for an exam in June now?? I don`t feel stupid at all haha
    You must feel like a total mug?
 
 
 
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