Just a really quick question. I'm given:
I have to find the solution given the conditions: y(0)=y'(0)=0
This is an initial value problem, and I get:
and G(x,z)=sink(x-z)/k (x>z)
Right from here I should easily be able to find the solution by carrying out the integral:
INT(from 0 to x) [2coskz*sink(x-z)dz] but even though the obtained answer satisfies the boundary conditions, I've been told that this is not quite correct. Something like G(x-z) and G(z,z)=0 was mentioned, but I can't see how this will give me the correct answer. In any case, if you can tell me why my approach is incorrect, that would be very helpful.
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Quick Green's function q watch
- Thread Starter
Last edited by Spire; 21-01-2010 at 12:32.
- 20-01-2010 21:04
- 21-01-2010 00:51
You want y(x) = integral of f(z) G(x,z) dz, but you've got integral of f(x) G(x,z) dz.