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# Edexcel C4 Monday 25th January 2010 (AM) watch

1. was it costheta=19/26?
2. (Original post by u4m1r)
hey there

what did you guys get for the area of the loopy thing? Question 7 i think. I got 324 but does it have to be doubled??

And also the length of vector AY i got 29.7 or 27.9 something like that??
and for question 7) you couldve just t=3 and t=-3 and you wouldve gotten the answer as 648, or do it with t=3 and t=0 and get 324( what you got) then double it which is 648
3. (Original post by hussam1992)
yeah you shouldve drawn it and used the sin or cosine law/rule to get:

(AY/sin90)=(4root26)/sin(90-angle of feta)

you had cos feta = 19/25

cant remember how i solved it exactly, but i think it was either 21.7 , 27.9 , 27.1 or 29.7 (sry for not being precise)

I used pythagoras. It said YX was perpendicular to L1 or summin, nice right angled triangle i think.
4. (Original post by sulexk)
I can remember getting 7614/something

for Q(7) but I cannot recall the denominator, sorry

thanks!
thats probably wrong, cuz you shouldve had an integer at the end
5. (Original post by ojpowermake)
I used pythagoras. It said YX was perpendicular to L1 or summin, nice right angled triangle i think.
So you worked out YX then used it? could work too cuz the triangle was a right angled triangle, you couldve used sin law, cosine law or pythagoras i guess. All of them should give you the same answer.
6. (Original post by sulexk)
was it costheta=19/26?
i believe so
7. (Original post by hussam1992)
and for question 7) you couldve just t=3 and t=-3 and you wouldve gotten the answer as 648, or do it with t=3 and t=0 and get 324( what you got) then double it which is 648
DAMN!!
8. (Original post by hussam1992)
So you worked out YX then used it? could work too cuz the triangle was a right angled triangle, you couldve used sin law, cosine law or pythagoras i guess. All of them should give you the same answer.
Shoulda done it the shorter way - Y was not nice numbers
9. (Original post by u4m1r)
DAMN!!
you'll probably lose 1-2 marks max, i think
10. (Original post by ojpowermake)
Shoulda done it the shorter way - Y was not nice numbers
I think i got the answer wrong cuz i used the wrong angle, other than that it should be fine.
11. The funny thing is that i'm expecting an average of 90% UMS or more in C3 and C4 and im not sure im gonna get an average 80% UMS in C1 C2 and M1, ironic isnt it? anyway if i dont get an A in the AS level, will i still get the A* if i get the 90% average in C3 and C4?
12. Well, the values i used were still in my calculator so i can tell u i got 27.91
13. hey there guys, I made a slight error, in question (7), initially I wrote down the correct integral, but when integrating I forgot about the 10 for the second term, but I still obtained 30t^3, and the correct integral but since I got the integral of the second term incorrect(due to the lost 10) will I still get marks?
14. (Original post by ojpowermake)
Well, the values i used were still in my calculator so i can tell u i got 27.91
yeah i remember getting something.9 and i remember it was either a 27 or a 21, not sure :P
15. (Original post by hussam1992)
The funny thing is that i'm expecting an average of 90% UMS or more in C3 and C4 and im not sure im gonna get an average 80% UMS in C1 C2 and M1, ironic isnt it? anyway if i dont get an A in the AS level, will i still get the A* if i get the 90% average in C3 and C4?
I think it's 90% or more in C3 and C4. and 80% or more over AS and A2 together to get an A*
16. (Original post by hussam1992)
The funny thing is that i'm expecting an average of 90% UMS or more in C3 and C4 and im not sure im gonna get an average 80% UMS in C1 C2 and M1, ironic isnt it? anyway if i dont get an A in the AS level, will i still get the A* if i get the 90% average in C3 and C4?

yeah its possible. If you get say 100 in C3 and C4, thats 200 UMS already, you need 280 more to get an A from 4 modules. That is 70 in those. So you can get 70 in C1, C2 and you 2 applied modules which is a B at AS yet an A* at A2.
17. (Original post by sulexk)
hey there guys, I made a slight error, in question (7), initially I wrote down the correct integral, but when integrating I forgot about the 10 for the second term, but I still obtained 30t^3, and the correct integral but since I got the integral of the second term incorrect(due to the lost 10) will I still get marks?
Im not sure if there is a carry-on mark scheme/system, but if there is then you will lose 1 mark, if there isnt then you probably will lose from 1 to 3 marks (not sure just guessing)
18. (Original post by ojpowermake)
.
Agreed with ojpowermake with the 27.91....I remember a similar value (length of XY or AY right?)

(Original post by hussam1992)
.
Also, hussam1992 you need 80% average across the entire 6 units....so you could average 75% at C1, C2, M1 and M2 then 90% in C3 and C4 and get an A*
19. (Original post by u4m1r)
yeah its possible. If you get say 100 in C3 and C4, thats 200 UMS already, you need 280 more to get an A from 4 modules. That is 70 in those. So you can get 70 in C1, C2 and you 2 applied modules which is a B at AS yet an A* at A2.
Im guessing i might get around 95+% (not sure if i will get the marks for the graphs since i used a pencil, so i might lose an extra 12 marks, so it could be around 75% to 85%) in C1 75+% in C2 , 70% in M1, 95+% in S1, 90% in C3 and 95+% in C4
20. Will grade boundaries be higher than usual? potentially?

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