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     \int \dfrac{4}{(1+t)^3} dx

    Is it just:

     \dfrac{4x}{(1+t)^3} ?

    Thanks

    PS: t is a variable

    EDIT:

    Now that I think about it, the integral of t is not tx. Coz if you differentiate tx you get  x\frac{dt}{dx} + t am i rite?

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    You really need to know how t relates to x. You can't integrate without knowing this.
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    (Original post by meatball893)
    You really need to know how t relates to x. You can't integrate without knowing this.
    Ah ok, so if t was a constant, would what I wrote be correct?

    Thanks
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    (Original post by 2710)
    Ah ok, so if t was a constant, would what I wrote be correct?

    Thanks
    Yes. But don't forget to add a constant when integrating! :p:
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    (Original post by meatball893)
    Yes. But don't forget to add a constant when integrating! :p:
    Oh yeh lol. Thnx
 
 
 
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