The Student Room Group
Reply 1
jumblebumble
the real and imaginary parts of the complex number z = x + iy satisfy the equation (2-i)x - (1 + 3i)y - 7 =0

a) find the value of x and y
b) find the values of i) modulus of z ii) argz

how would i go about starting this question?

will rep - i'm just really confuddled

jb


Equate for real and imaginary numbers.

So to start you off:
z=x+iy so x=real and y=imaginary

2x-y=x (1)
-x-3=y (2)

so simplify:

y=x (1)
y=-x-3 (2)

so sub y into (2) and y=-y-3 therefore y=-1.5 etc...
Reply 2
JTeighty
Equate for real and imaginary numbers.

So to start you off:
z=x+iy so x=real and y=imaginary

2x-y=x (1)
-x-3=y (2)

so simplify:

y=x (1)
y=-x-3 (2)

so sub y into (2) and y=-y-3 therefore y=-1.5 etc...


the answers are x=3 and y=-1? :/
but thankyou anyway. jb
Reply 3
JTeighty's method is right, it's just that he's written the equations down wrong.

Start with:

2x-y-7=0

-3-3y=0

And solve as simultaneous equations. :smile:

(Expanding out, Re(0) and Im(0))

(Also, is the second part ok?)
Reply 4
Scallym
JTeighty's method is right, it's just that he's written the equations down wrong.

Start with:

2x-y-7=0

-3-3y=0

And solve as simultaneous equations. :smile:

(Expanding out, Re(0) and Im(0))

(Also, is the second part ok?)

Sorry, I wasn't concentrating properly. It's actually quite embarrasing that I'm doing F maths and despite that, i got those simple equations wrong. :'(
Reply 5
JTeighty
Sorry, I wasn't concentrating properly. It's actually quite embarrasing that I'm doing F maths and despite that, i got those simple equations wrong. :'(

That wasn't meant to be a criticism, sorry. I do it annoyingly often.:p:
Reply 6
Scallym
That wasn't meant to be a criticism, sorry. I do it annoyingly often.:p:


Don't worry, I didn't take it badly. I was just stating my stupidity.
Seems I'm too late. =)
Reply 8
jumblebumble
the real and imaginary parts of the complex number z = x + iy satisfy the equation (2-i)x - (1 + 3i)y - 7 =0

a) find the value of x and y
b) find the values of i) modulus of z ii) argz

how would i go about starting this question?

will rep - i'm just really confuddled

jb


Just out of interest, is this FP1 or FP2?
JTeighty
Just out of interest, is this FP1 or FP2?


This is FP1
Reply 10
Longorefisher
This is FP1


Thanks.

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