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# A2 chemistry watch

1. Kw is constant = 10^(-14) = [H+][OH-]
if [OH-] is 100 times greater, [H+] is 100 times smaller than before.

pH = -log to base 10 of [H+],
so it would naturally be less acidic by log to base 10 of 100 which is 2, as 10^2 = 100. So add 2 to your pH from previous calculation in c.

Oh gosh, i am a bit drunk now, pardon me if this is wrong.
2. (Original post by shengoc)
Kw is constant = 10^(-14) = [H+][OH-]
if [OH-] is 100 times greater, [H+] is 100 times smaller than before.

pH = -log to base 10 of [H+],
so it would naturally be less acidic by log to base 10 of 100 which is 2, as 10^2 = 100. So add 2 to your pH from previous calculation in c.

Oh gosh, i am a bit drunk now, pardon me if this is wrong.
Yeah i don't think that's right cause i tried but the answer for this is that pH = 8??????
3. but you probably got a hangover now so allow it lol..... anyone else please?
4. anyone?
5. there must be someone who can answer this???????
6. problem solved!!!!

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