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    I really don't know how to do this. I find it easy to do in actual displayed formula, but when they ask for it on skeletal, I just don't know how to represent the group on different side of the double bond?:confused: Anyone know what I'm getting at?
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    http://en.wikipedia.org/wiki/Cis-tra...anic_chemistry

    See the examples of the cis/trans-pentenes on the left.
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    erm..really don't see the problem.

    Isn't it just ie propene. CH3HC=CH2
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    (Original post by Casshern1456)
    erm..really don't see the problem.

    Isn't it just ie propene. CH3HC=CH2
    what you mentioned is structural formula, but organic chemists, for extreme simplicity, they simply just use lines to indicate the hydrocarbons.

    a turning point indicates a new carbon.
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    (Original post by shengoc)
    what you mentioned is structural formula, but organic chemists, for extreme simplicity, they simply just use lines to indicate the hydrocarbons.

    a turning point indicates a new carbon.
    Or not, if you have an alkyne... or a ketene... :tongue:
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    (Original post by shengoc)
    what you mentioned is structural formula, but organic chemists, for extreme simplicity, they simply just use lines to indicate the hydrocarbons.

    a turning point indicates a new carbon.
    For A-level's they don't normally tell you to draw out a compound in skeletal form.
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    (Original post by Casshern1456)
    For A-level's they don't normally tell you to draw out a compound in skeletal form.

    They do on the OCR spec
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    (Original post by _Andrew_)
    They do on the OCR spec
    Perhaps. Most people including me are on AQA spec.
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    (Original post by cpchem)
    Or not, if you have an alkyne... or a ketene... :tongue:
    i stand corrected with my wording.
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    (Original post by cpchem)
    Or not, if you have an alkyne... or a ketene... :tongue:
    Or an allene :p:
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    (Original post by Kyri)
    Or an allene :p:
    Indeed. Or cumulenes more generally...
 
 
 
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